Please consider the following two if() structures. The first one fails, yet
the second works. Why? FWIW, I got the syntax of the first out of a working
page. I figured moving it to another page would be harmless. What's going on
here? The only major difference between the two pages that I can see so far
is that in the new page (where the first if() structure fails), the control
imgname is in a <form runat="server" method="post"> whereas in the page it
came from, there is no <Form> at all on the page. Could that have some
relevance?
// This one fails
if(v_incoming != "")
{
imgname.value = v_incoming; // this errors out with message: 'imgname' is
undefined.
}
// This one works
if(v_incoming != "")
{
var obj_imgname = document.all("i mgname");
obj_imgname.val ue = v_incoming; //no problems
}
here is the definition of imgname:
<input type="text" id="imgname" size="40" value="http://" NAME="imgname">
Thanks!
3  1119 
yes, having a form defined matters.
<html>
<body>
<input type=text name=imgname id=imgname1>
<form name=myForm>
<input type=text name=imgname id=imgname1>
</form>
</body>
</html>
document.imgnam e.value //refers to the first one
document.myForm .imgname.value //refers to the second (as it is a child
of myForm)
document.all("i mgname") // is obsolete and
should never be used - would return an array
document.getEle mentsByTag('img name')[0] // referes to the first one
document.getEle mentsByTag('img name')[1] // referes to the second one
as id are required to be unique in a document unlike names, the following
should work
document.getEle mentById('imgna me1') // referes to the first one
document.getEle mentById('imgna me2') // referes to the second one
-- bruce (sqlwork.com)
"Fred" <th************ *@skruspammers. com> wrote in message
news:%2******** *******@TK2MSFT NGP11.phx.gbl.. . Please consider the following two if() structures. The first one fails,
yet the second works. Why? FWIW, I got the syntax of the first out of a
working page. I figured moving it to another page would be harmless. What's going
on here? The only major difference between the two pages that I can see so
far is that in the new page (where the first if() structure fails), the
control imgname is in a <form runat="server" method="post"> whereas in the page it
came from, there is no <Form> at all on the page. Could that have some
relevance?
// This one fails
if(v_incoming != "")
{
imgname.value = v_incoming; // this errors out with message: 'imgname'
is undefined.
}
// This one works
if(v_incoming != "")
{
var obj_imgname = document.all("i mgname");
obj_imgname.val ue = v_incoming; //no problems
}
here is the definition of imgname:
<input type="text" id="imgname" size="40" value="http://" NAME="imgname">
Thanks!
In your first example - imagename is undefined. An easier way to do this is to use your form name.
example:
<form name="Form1">
<input type="text" id="imgname" size="40" value="http://" NAME="imgname">
</form>
if(v_incoming != "")
{
Form1.imgname.v alue = v_incoming;
}
Bobby Ryzhy
bobby@ domain below http://weekendtech.net
On Mon, 12 Jul 2004 14:36:37 -0700, "Fred" <th************ *@skruspammers. com> wrote: Please consider the following two if() structures. The first one fails, yet
the second works. Why? FWIW, I got the syntax of the first out of a working
page. I figured moving it to another page would be harmless. What's going on
here? The only major difference between the two pages that I can see so far
is that in the new page (where the first if() structure fails), the control
imgname is in a <form runat="server" method="post"> whereas in the page it
came from, there is no <Form> at all on the page. Could that have some
relevance?
// This one fails
if(v_incomin g != "")
{
imgname.value = v_incoming; // this errors out with message: 'imgname' is
undefined.
}
// This one works
if(v_incomin g != "")
{
var obj_imgname = document.all("i mgname");
obj_imgname.val ue = v_incoming; //no problems
}
here is the definition of imgname:
<input type="text" id="imgname" size="40" value="http://" NAME="imgname">
Thanks!
Bobby Ryzhy
bobby @ domain below http://weekendtech.net
Wow, thanks. I guess I'll have to take JavaScript a bit more seriously!
"bruce barker" <no***********@ safeco.com> wrote in message
news:%2******** ********@TK2MSF TNGP12.phx.gbl. .. yes, having a form defined matters.
<html>
<body>
<input type=text name=imgname id=imgname1>
<form name=myForm>
<input type=text name=imgname id=imgname1>
</form>
</body>
</html>
document.imgnam e.value //refers to the first one
document.myForm .imgname.value //refers to the second (as it is a
child of myForm)
document.all("i mgname") // is obsolete and
should never be used - would return an array
document.getEle mentsByTag('img name')[0] // referes to the first one
document.getEle mentsByTag('img name')[1] // referes to the second one
as id are required to be unique in a document unlike names, the following
should work
document.getEle mentById('imgna me1') // referes to the first one
document.getEle mentById('imgna me2') // referes to the second one
-- bruce (sqlwork.com)
"Fred" <th************ *@skruspammers. com> wrote in message
news:%2******** *******@TK2MSFT NGP11.phx.gbl.. . Please consider the following two if() structures. The first one fails, yet the second works. Why? FWIW, I got the syntax of the first out of a
working page. I figured moving it to another page would be harmless. What's
going on here? The only major difference between the two pages that I can see so
far is that in the new page (where the first if() structure fails), the
control imgname is in a <form runat="server" method="post"> whereas in the page
it came from, there is no <Form> at all on the page. Could that have some
relevance?
// This one fails
if(v_incoming != "")
{
imgname.value = v_incoming; // this errors out with message: 'imgname'
is undefined.
}
// This one works
if(v_incoming != "")
{
var obj_imgname = document.all("i mgname");
obj_imgname.val ue = v_incoming; //no problems
}
here is the definition of imgname:
<input type="text" id="imgname" size="40" value="http://"
NAME="imgname">
Thanks!
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