Creating a list of Mondays for a year

[Chris]

Is there a way to make python create a list of Mondays for a given year?

For example,

mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

[skip]

Chris> Is there a way to make python create a list of Mondays for a
Chris> given year? For example,

Chris> mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
Chris> '1/31/2005','2/7/2005', ... ]

How about:

import datetime

oneday = datetime.timede lta(days=1)
oneweek = datetime.timede lta(days=7)

year = 2005

start = datetime.date(y ear=year, month=1, day=1)
while start.weekday() != 0:
start += oneday

days = []
while start.year == year:
days.append(sta rt)
start += oneweek

print days

Skip

[Peter Hansen]

Chris wrote:

Is there a way to make python create a list of Mondays for a given year?

For example,

mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

from datetime import date, timedelta

def mondays(year):
'''generate all days that are Mondays in the given year'''
jan1 = date(year, 1, 1)

# find first Monday (which could be this day)
monday = jan1 + timedelta(days= (7-jan1.weekday()) % 7)

while 1:
if monday.year != year:
break
yield monday
monday += timedelta(days= 7)

[str(x) for x in mondays(2005)]

['2004-01-05', '2004-01-12', ... '2004-12-27']

Extension to support any day of the week (including renaming the
function!) is left as an exercise to the reader. ;-)

--
Peter

[George Sakkis]

"Chris" <se***@yahoo.co m> wrote:

Is there a way to make python create a list of Mondays for a given year?

For example,

mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

Get the dateutil package (https://moin.conectiva.com.br/DateUtil):

import dateutil.rrule as rrule
from datetime import date

mondays2005 = tuple(rrule.rru le(rrule.WEEKLY ,
dtstart=date(20 05,1,1),
count=52,
byweekday=rrule .MO))

George

[waldemar.osuch]

Consider also dateutil written by Gustavo Niemeyer
and found at:
https://moin.conectiva.com.br/DateUtil

from dateutil.rrule import *
list(rrule(WEEK LY, byweekday=MO, dtstart=date(20 05,1,1), until=date(2005 ,12,31)))

The library may be a little intimidating at first it is worth learning.

waldek

[Peter Hansen]

George Sakkis wrote:

"Chris" <se***@yahoo.co m> wrote:

Is there a way to make python create a list of Mondays for a given year?

Get the dateutil package (https://moin.conectiva.com.br/DateUtil):

import dateutil.rrule as rrule
from datetime import date

mondays2005 = tuple(rrule.rru le(rrule.WEEKLY ,
dtstart=date(20 05,1,1),
count=52,
byweekday=rrule .MO))

Count should probably be at least "53" to catch the years when there are
that many Mondays.... such as 2001. Unfortunately, I suspect that will
screw it up for other years where there are only 52 (but I don't know
this dateutil package so someone who does would have to say for sure).

-Peter

[Paul Rubin]

Chris <se***@yahoo.co m> writes:

Is there a way to make python create a list of Mondays for a given year?
mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

This is pretty inefficient but it's conceptually the simplest:

def mondays(year):
from calendar import weekday, monthrange
return [('%d/%d/%d'%(month,day, year))
for month in xrange(1,13)
for day in xrange(1,1+mont hrange(year,mon th)[1])
if weekday(year,mo nth,day) == 0]

[George Sakkis]

"Peter Hansen" <pe***@engcorp. com> wrote:

George Sakkis wrote:

"Chris" <se***@yahoo.co m> wrote:

Is there a way to make python create a list of Mondays for a given year?

Get the dateutil package (https://moin.conectiva.com.br/DateUtil):

import dateutil.rrule as rrule
from datetime import date

mondays2005 = tuple(rrule.rru le(rrule.WEEKLY ,
dtstart=date(20 05,1,1),
count=52,
byweekday=rrule .MO))

Count should probably be at least "53" to catch the years when there are
that many Mondays.... such as 2001. Unfortunately, I suspect that will
screw it up for other years where there are only 52 (but I don't know
this dateutil package so someone who does would have to say for sure).

-Peter

Sorry, my bad; waldek in the post below got it right. Here's yet
another way that doesn't use the count or until keywords:

from itertools import takewhile
mondays2001 = tuple(takewhile (lambda d: d.year==2001, rrule.rrule(rru le.WEEKLY,
dtstart=date(20 01,1,1),
byweekday=rrule .MO))) print len(mondays2001 )

53

George

[Chris]

Thanks to everyone for your help!

That fit the need perfectly.

In article <MP************ ************@ne ws2.atlantic.ne t>,
se***@yahoo.com says...

Is there a way to make python create a list of Mondays for a given year?

For example,

mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

[Charles Krug]

On Mon, 19 Sep 2005 12:10:04 GMT, Chris <se***@yahoo.co m> wrote:

Thanks to everyone for your help!

That fit the need perfectly.

In article <MP************ ************@ne ws2.atlantic.ne t>,
se***@yahoo.com says...

Is there a way to make python create a list of Mondays for a given year?

For example,

mondays = ['1/3/2005','1/10/2005','1/17/2005','1/24/2005',
'1/31/2005','2/7/2005', ... ]

You can also calculate it using the Julian Day Number. Google on
astronomical calculations, or read the introduction to one of the
Numerical Recipies. . . books for a discussion and algorithm.