Could some PHP guru please help me? I am have a drop down list, whose
options are read in dynamically from a table in a MySQL database. one
of the items being read in is an URL. I am
unable to display this URL in the drop down list. The following is the
code snippet I am using:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school,
schoolurl FROM
schoolproject_p ics ORDER BY
year");
echo "<select name=\"semester \">";
while(list($yea r, $semester, $school, $schoolurl) =
mysql_fetch_arr ay($sql_query)) {
echo "<option value=\"$year\" >$year $semester <a
href=\"$schoolu rl\">$school</a></option>";
}
When the drop down list is displayed, I do not see the URL. Could
someone please point out what exactly I am doing wrong? Thanks in
advance for your help, any help would be greatly appreciated. 3 4386 cp**********@ya hoo.com wrote:
Could some PHP guru please help me? I am have a drop down list, whose
options are read in dynamically from a table in a MySQL database. one
of the items being read in is an URL. I am
unable to display this URL in the drop down list. The following is the
code snippet I am using:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school,
schoolurl FROM
schoolproject_p ics ORDER BY
year");
echo "<select name=\"semester \">";
while(list($yea r, $semester, $school, $schoolurl) =
mysql_fetch_arr ay($sql_query)) {
echo "<option value=\"$year\" >$year $semester <a
href=\"$schoolu rl\">$school</a></option>";
}
When the drop down list is displayed, I do not see the URL. Could
someone please point out what exactly I am doing wrong? Thanks in
advance for your help, any help would be greatly appreciated.
you can't have <tags inside of an <optiontag, you can either just
display the url inline, $year $semester $school, or you will need to
put it in the option value field and put $year elsewhere.
Flamer.
Try using this:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school,
schoolurl FROM schoolproject_p ics ORDER BY year");
echo "<select name=\"semester \">";
while(list($yea r, $semester, $school, $schoolurl) =
mysql_fetch_arr ay($sql_query))
{
echo "<option value=\"$year\"
onclick=\"windo w.open('$school url');\">$schoo l ($year
$semester)</option>";
}
Hope it helps.. You cannot have an href inside of an option display.
But you can use some nifty JS to help you out :) cp**********@ya hoo.com wrote:
Could some PHP guru please help me? I am have a drop down list, whose
options are read in dynamically from a table in a MySQL database. one
of the items being read in is an URL. I am
unable to display this URL in the drop down list. The following is the
code snippet I am using:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school,
schoolurl FROM
schoolproject_p ics ORDER BY
year");
echo "<select name=\"semester \">";
while(list($yea r, $semester, $school, $schoolurl) =
mysql_fetch_arr ay($sql_query)) {
echo "<option value=\"$year\" >$year $semester <a
href=\"$schoolu rl\">$school</a></option>";
}
When the drop down list is displayed, I do not see the URL. Could
someone please point out what exactly I am doing wrong? Thanks in
advance for your help, any help would be greatly appreciated.
"Robert" <ro*******@gmai l.comwrote in news:1155543441 .183922.320090
@m79g2000cwm.go oglegroups.com: cp**********@ya hoo.com wrote:
>Could some PHP guru please help me? I am have a drop down list, whose options are read in dynamically from a table in a MySQL database. one of the items being read in is an URL. I am unable to display this URL in the drop down list. The following is
the
>code snippet I am using:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school, schoolurl FROM schoolproject_p ics ORDER
BY
>year"); echo "<select name=\"semester \">"; while(list($yea r, $semester, $school, $schoolurl) = mysql_fetch_ar ray($sql_query) ){ echo "<option value=\"$year\" >$year $semester <a href=\"$school url\">$school</a></option>"; }
When the drop down list is displayed, I do not see the URL. Could someone please point out what exactly I am doing wrong? Thanks in advance for your help, any help would be greatly appreciated.
:: top posting fixed ::
Try using this:
$sql_query = mysql_query("SE LECT DISTINCT year, semester, school,
schoolurl FROM schoolproject_p ics ORDER BY year");
echo "<select name=\"semester \">";
while(list($yea r, $semester, $school, $schoolurl) =
mysql_fetch_arr ay($sql_query))
{
echo "<option value=\"$year\"
onclick=\"windo w.open('$school url');\">$schoo l ($year
$semester)</option>";
}
Hope it helps.. You cannot have an href inside of an option display.
But you can use some nifty JS to help you out :)
Why use the above method? It not only relies on javascript to work, but
also opens a new window. You may as well add an alertbox telling the
user you hate them.
--
Karl Groves www.karlcore.com This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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