Multiple selection + table

[Lori Costache]

Hi guys,
I have a problem with multiple selection
I have a list with 8 options in pull-down menu. For each option I have a price.
Something like that :Element Price

Table 10
Sofa 20

<SELECT NAME=myfurnitur e[] id=myfurniture[] class=third multiple>
<OPTION VALUE="Table">T able </OPTION>
<OPTION VALUE="Sofa">So fa</OPTION>.....

I do that:

foreach ($myfurniture As $Item)
{
echo "<li>" . $Item . "</li>";
if($Item=True)
{
switch ($myfurniture)
{
case $myfurniture = "Table";

echo "<p class=second>Pr ice is: <span class=five> 10;</span></p>";
break;......
But I receive the result only and always for the last element from myfurniture array
Need help

I didnt find anything to treat something like
Thank You !!!

[Darryl Porter]

Your switch it using incorrect syntax, the case should simply look like the
example below:

case "TABLE":

You do not need $myfurnaure ="Table";--this is wrong.

Also, take note that I used a colon after my case statement and not a
semi-colon.
"Lori Costache" <nc*******@hotm ail.com> wrote in message
news:9c******** *************** ***@posting.goo gle.com...

Hi guys,
I have a problem with multiple selection
I have a list with 8 options in pull-down menu. For each option I have a price. Something like that :Element Price

Table 10
Sofa 20

<SELECT NAME=myfurnitur e[] id=myfurniture[] class=third multiple>
<OPTION VALUE="Table">T able </OPTION>
<OPTION VALUE="Sofa">So fa</OPTION>.....

I do that:

foreach ($myfurniture As $Item)
{
echo "<li>" . $Item . "</li>";
if($Item=True)
{
switch ($myfurniture)
{
case $myfurniture = "Table";

echo "<p class=second>Pr ice is: <span class=five> 10;</span></p>";
break;......
But I receive the result only and always for the last element from myfurniture array

Need help

I didnt find anything to treat something like
Thank You !!!

[Darryl Porter]

correct:

case "Table":

NOT

case "TABLE":

"Darryl Porter" <dp******@woh.r r.com> wrote in message
news:0U******** *************@t wister.neo.rr.c om...

Your switch it using incorrect syntax, the case should simply look like the example below:

case "TABLE":

You do not need $myfurnaure ="Table";--this is wrong.

Also, take note that I used a colon after my case statement and not a
semi-colon.
"Lori Costache" <nc*******@hotm ail.com> wrote in message
news:9c******** *************** ***@posting.goo gle.com...

Hi guys,
I have a problem with multiple selection
I have a list with 8 options in pull-down menu. For each option I have a

price.

Something like that :Element Price

Table 10
Sofa 20

<SELECT NAME=myfurnitur e[] id=myfurniture[] class=third multiple> <OPTION VALUE="Table">T able </OPTION>
<OPTION VALUE="Sofa">So fa</OPTION>.....

I do that:

foreach ($myfurniture As $Item)
{
echo "<li>" . $Item . "</li>";
if($Item=True)
{
switch ($myfurniture)
{
case $myfurniture = "Table";

echo "<p class=second>Pr ice is: <span class=five> 10;</span></p>";
break;......
But I receive the result only and always for the last element from

myfurniture array

Need help

I didnt find anything to treat something like
Thank You !!!

[Lori Costache]

"Darryl Porter" <dp******@woh.r r.com> wrote in message news:<xV******* **************@ twister.neo.rr. com>...

correct:

case "Table":

NOT

case "TABLE":

"Darryl Porter" <dp******@woh.r r.com> wrote in message
news:0U******** *************@t wister.neo.rr.c om...

Your switch it using incorrect syntax, the case should simply look like

the

example below:

case "TABLE":

You do not need $myfurnaure ="Table";--this is wrong.

Also, take note that I used a colon after my case statement and not a
semi-colon.

Thank You Darryl

But STILL didnt work !!
Have you ever try something similar with my table? I modified maybe 20
times and 0, nada ! Im not specialist so please try to be pacient !