Streaming text output.

[Handover Phist]

I have a call to wget that transferres a file of about 30 meg at about 1
meg per second. This has the user waiting 30 seconds or so before the
page responds. What I want to do is send the ouput of wget while it's
happening, which is proving a bit iffy.

$modprog = popen('/path/to/wget/shell/script', 'r');
$buffer = fopen($modprog, "1");
$display = fgetc($buffer);
echo $display;
pclose($modprog );

doesn't work for what may be obvious reasons to those in the community.
I don geddit. Any suggestions please?

--
Virtue is its own punishment.

[Nikolai Chuvakhin]

Handover Phist <ja***@jason.we bsterscafe.com> wrote
in message news:<slrnbuets b.16r.ja***@jas on.websterscafe .com>...

I have a call to wget that transferres a file of about 30 meg
at about 1 meg per second.

Why do you have to involve wget at all? Let's say you need to
dump into the standard output a file that resides at this URL:

http://www.yourhost.com/your/path/your.file

Here's what you can do:

$host = 'www.yourhost.c om';
$path = 'your/path/your.file';
$fp = fsockopen ($host, '80');
if ($fp) {
fputs($fp, 'GET '.$path." HTTP/1.0\r\nHost: ".$host."\r\n") ;
} else {
die ('Oops... Nobody home...');
}
while (!feof ($fp)) {
echo fgets ($fp, 10240);
}
fclose ($fp);

Another workable alternative would be to use cURL:

http://www.php.net/curl

By default, curl_exec() will do exactly what you want: dump
a remote file into the standard output...

Cheers,
NC

[Rahul Anand]

Handover Phist <ja***@jason.we bsterscafe.com> wrote in message news:<slrnbuets b.16r.ja***@jas on.websterscafe .com>...

I have a call to wget that transferres a file of about 30 meg at about 1
meg per second. This has the user waiting 30 seconds or so before the
page responds. What I want to do is send the ouput of wget while it's
happening, which is proving a bit iffy.

$modprog = popen('/path/to/wget/shell/script', 'r');
$buffer = fopen($modprog, "1");
$display = fgetc($buffer);
echo $display;
pclose($modprog );

doesn't work for what may be obvious reasons to those in the community.
I don geddit. Any suggestions please?

I think popen returns a file pointer so you do not need

$buffer = fopen($modprog, "1");

You can directly call

$display = fgetc($modprog) ;

Hope it will help....

--Rahul