OpenFileDialog - how to select files by coding???

[Sharon]

I’m using OpenFileDialog class in a specific InitialDirector y and I want that
files will be selected in the opened dialog when I call ShowDialog().
Actually I wish to select all files in the directory automatically by code.

Is it doable?
How??

--
Regards
Sharon G.

[Nicholas Paldino [.NET/C# MVP]]

Sharon,

I don't believe that this is possible. You might be able to hack it by
getting the window handle for the file dialog and then getting the handle
for the listview, and then sending the message to select every item, but
that would seem excessive.

Does the possibility exist that only some files in the directory would
be selected, or will they always be selecting all of the files in the
directory? If it is the latter, then you might want to consider using a
DirectoryBrowse Dialog (I believe that is what it is called), as it will let
you select directories.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"Sharon" <Sh****@discuss ions.microsoft. com> wrote in message
news:6A******** *************** ***********@mic rosoft.com...

I'm using OpenFileDialog class in a specific InitialDirector y and I want
that
files will be selected in the opened dialog when I call ShowDialog().
Actually I wish to select all files in the directory automatically by
code.

Is it doable?
How??

--
Regards
Sharon G.

[Cor Ligthert]

Sharon,

When you want to have all files why are you than using OpenFileDialog and
not just

DirectoryInfo
http://msdn.microsoft.com/library/de...snametopic.asp

A sample to get those filenames is in this link.

I hope this helps?

Cor

[Sharon]

Eventually I'm using the native API FindWindow() ans SendMessge(), but I can
find what message to send to the Form.ListBox.
Can anybody tell me how to complete and fix the following call so the
ListBox will select all files in it?

SendMessage(lis tviewHandle, 0x0111, ...

I already obtained the listviewHandle but all other parameters are missing
for me, especially I need the actual value of the message, like 0x702e for
Tiles view.

[Sharon]

Ok, I have the answer:

[DllImport("user 32.dll", EntryPoint="Sen dMessageA",
CallingConventi on=CallingConve ntion.StdCall,C harSet=CharSet. Ansi)]
private static extern uint SendMessage(uin t Hdc, uint Msg_Const, uint
wParam, uint lParam);

[DllImport("user 32.dll", EntryPoint="Fin dWindowExA",
CallingConventi on=CallingConve ntion.StdCall,C harSet=CharSet. Ansi)]
private static extern uint FindWindowEx(ui nt hwndParent, uint
hwndChildAfter, string lpszClass, string lpszWindow);

protected override void WndProc(ref Message m)
{
// Leting the Form take care off all messages.
base.WndProc(re f m);

if( m.Msg == 289 ) // Notify of message loop
{
uint dialogHandle = (uint)m.LParam; // Handle of the file dialog

if( dialogHandle != m_lastDialogHan dle ) // Only when not already changed
{
// Getting the handle of the ListBox in the OpenFileDialog dialog.
uint listviewHandle = FindWindowEx(di alogHandle, 0,
"SHELLDLL_DefVi ew", "");

// Sending message to the ListBox to set the view to Thumbnails
//Icons=0x7029, List=0x702b, Details=0x702c, Thumbnails=0x70 2d,
Tiles=0x702e
SendMessage(lis tviewHandle, 0x0111/*WM_COMMAND*/, (uint)0x702d, 0);

// Sending message to the ListBox to select all items.
SendMessage(lis tviewHandle, 0x0111/*WM_COMMAND*/, (uint)0x0001702 1,
(uint)0);

// Remember last handle
m_lastDialogHan dle = dialogHandle;
}
}
}