Need help replacing a specific <a href ... </a>

[Sorby]

Hi
I've been coding in PHP for a little while now and was starting to feel
pretty confident but then realise I need to understand regular expressions
to solve a particular problem I've got ... What a horrible can of worms
regex is!! (to the uninitiated at least).

I realise that if I spend the next few weeks researching regex I'll probably
find the answer but I was wondering if anyone here would kindly help speed
up the process?

Basically I am grabbing the html from another URL, finding a specific <a
href .. </a> block and replacing the contents of that block with another
link. (n.b. the code examples below are pseudo code - I realise I need to
'escape' some characters)

Here's how I'm grabbing the source html :
$html = join ("", file (http://www.sitexyz.com/index.htm));

the link I want to replace looks something like :
<a href="http://www.sitexyz.com/page2"><img height="120"
src="origpic.jp g"></a>
Note - the only thing I know to be constant about the above link is that the
height is always 120 - the link destination and source image are completely
unpredictable.

Here's a variable holding the replacement link to my site using a different
image :
$newlink = "<a href="http://www.mysite.com" ><img height="120"
src="mypic.jpg" ></a>";

So... how do I use preg_replace() or ereg_replace() to find the <a href ..
</a> block encompassing an image of height 120 and replace it with the
contents of my $newlink variable?

*** To precis my question ... How do I replace an HTML link (where all I
know is the image height) with a link of my own? ***

TIA!

p.s. I promise I'll go and sit on the top of a mountain and not come down
until I've memorised & understood everything about regex ... once I've
sorted this problem! :o)

--
Sorby

[Pedro Graca]

Sorby wrote:

Here's how I'm grabbing the source html :
$html = join ("", file (http://www.sitexyz.com/index.htm));
You realize the parameter to file() should be between quotes, right?
the link I want to replace looks something like :
<a href="http://www.sitexyz.com/page2"><img height="120"
src="origpic.jp g"></a>
Note - the only thing I know to be constant about the above link is that the
height is always 120 - the link destination and source image are completely
unpredictable.
What about the order they appear in?
What about white space (including newlines)?
What about other attributes?
Here's a variable holding the replacement link to my site using a different
image :
$newlink = "<a href="http://www.mysite.com" ><img height="120"
src="mypic.jpg" ></a>";

So... how do I use preg_replace() or ereg_replace() to find the <a href ..
</a> block encompassing an image of height 120 and replace it with the
contents of my $newlink variable?
You're better off using an HTML parser than relying on the structure of
the HTML you're fetching.

Anyway, if they don't ever change, here's a starting point:

<?php
error_reporting (E_ALL);
ini_set('displa y_errors', '1');

$x = '... <a href="http://www.sitexyz.com/page2">';
$x .= '<img height="120" src="origpic.jp g"></a> ...';

$newlink = '<a href="http://www.mysite.com" >';
$newlink .='<img height="120" src="mypic.jpg" ></a>';

$y = preg_replace('@ <a href="[^"]+"><img height="120" src="[^"]+"></a>@',
$newlink, $x);

echo "$x\n$y\n";
?>

*** To precis my question ... How do I replace an HTML link (where all I
know is the image height) with a link of my own? ***

HTML links do not always have an image associated with them!
--
USENET would be a better place if everybody read: : mail address :
http://www.catb.org/~esr/faqs/smart-questions.html : is valid for :
http://www.netmeister.org/news/learn2quote2.html : "text/plain" :
http://www.expita.com/nomime.html : to 10K bytes :

[Sorby]

"Pedro Graca" <he****@hotpop. com> wrote in message
news:c6******** ****@ID-203069.news.uni-berlin.de...

Sorby wrote:

Here's how I'm grabbing the source html :
$html = join ("", file (http://www.sitexyz.com/index.htm));
You realize the parameter to file() should be between quotes, right?

Yes - thanks. I just typed it in that way - but in my source code it has
quotes.

the link I want to replace looks something like :
<a href="http://www.sitexyz.com/page2"><img height="120"
src="origpic.jp g"></a>
Note - the only thing I know to be constant about the above link is that the height is always 120 - the link destination and source image are completely unpredictable.

What about the order they appear in?

Here is an exact cut'n'paste of the bit I want to replace.

<a href="/1/files/small/north/page2.htm"><img height="120" hspace="0"
align="left" vspace="0" border="0" width="80" alt="original photo"
src="http://www.mysite.com/origpic.jpg" /></a>
What about white space (including newlines)?
I don't think this will be a problem. Hope not anyway. All the examples I've
seen are as above and with no line-breaks/carriage-returns.
What about other attributes?
I've included them in the new example above.

Here's a variable holding the replacement link to my site using a different image :
$newlink = "<a href="http://www.mysite.com" ><img height="120"
src="mypic.jpg" ></a>";

So... how do I use preg_replace() or ereg_replace() to find the <a href ... </a> block encompassing an image of height 120 and replace it with the
contents of my $newlink variable?

You're better off using an HTML parser than relying on the structure of
the HTML you're fetching.

Am I relying on the structure of the HTML I'm fetching? If the structure of
the HTML changes over time but the image height remains 120 then the code
should still work, right?
Anyway, if they don't ever change, here's a starting point:

<?php
error_reporting (E_ALL);
ini_set('displa y_errors', '1');

$x = '... <a href="http://www.sitexyz.com/page2">';
$x .= '<img height="120" src="origpic.jp g"></a> ...';

$newlink = '<a href="http://www.mysite.com" >';
$newlink .='<img height="120" src="mypic.jpg" ></a>';

$y = preg_replace('@ <a href="[^"]+"><img height="120" src="[^"]+"></a>@',
$newlink, $x);

echo "$x\n$y\n";
?>

Thanks for taking the time to post this solution Pedro. I will try it out
now.

*** To precis my question ... How do I replace an HTML link (where all I
know is the image height) with a link of my own? ***

HTML links do not always have an image associated with them!

Good point but thankfully I am assured that in my case the links I'm looking
for will always have an image.

Thanks again - your help is greatly appreciated.

--
Sorby

[Sorby]

"Pedro Graca" <he****@hotpop. com> wrote in message
news:c6******** ****@ID-203069.news.uni-berlin.de...

Sorby wrote:

Here's how I'm grabbing the source html :
$html = join ("", file (http://www.sitexyz.com/index.htm));

You realize the parameter to file() should be between quotes, right?

the link I want to replace looks something like :
<a href="http://www.sitexyz.com/page2"><img height="120"
src="origpic.jp g"></a>
Note - the only thing I know to be constant about the above link is that the height is always 120 - the link destination and source image are completely unpredictable.

What about the order they appear in?
What about white space (including newlines)?
What about other attributes?

Here's a variable holding the replacement link to my site using a different image :
$newlink = "<a href="http://www.mysite.com" ><img height="120"
src="mypic.jpg" ></a>";

So... how do I use preg_replace() or ereg_replace() to find the <a href ... </a> block encompassing an image of height 120 and replace it with the
contents of my $newlink variable?

You're better off using an HTML parser than relying on the structure of
the HTML you're fetching.

Anyway, if they don't ever change, here's a starting point:

<?php
error_reporting (E_ALL);
ini_set('displa y_errors', '1');

$x = '... <a href="http://www.sitexyz.com/page2">';
$x .= '<img height="120" src="origpic.jp g"></a> ...';

Sorry - I probably wasn't clear enough - the href link and the image source
name could be anything - I can't predict them - or even part of them.

--
Sorby

[Pedro Graca]

Sorby wrote:

"Pedro Graca" <he****@hotpop. com> wrote in message
news:c6******** ****@ID-203069.news.uni-berlin.de...

$x = '... <a href="http://www.sitexyz.com/page2">';
$x .= '<img height="120" src="origpic.jp g"></a> ...';

Sorry - I probably wasn't clear enough - the href link and the image source
name could be anything - I can't predict them - or even part of them.

It's ok, just try it with with different $x's :)
$x = '<a href="one"><img src="one"/></a>';
# $y = preg_replace();

$x = '<a href="two"><img src="two"></a>';
# $y = preg_replace();

$x = '<a href="three"><i mg src="three"></a>';
# $y = preg_replace();

....

--
USENET would be a better place if everybody read: : mail address :
http://www.catb.org/~esr/faqs/smart-questions.html : is valid for :
http://www.netmeister.org/news/learn2quote2.html : "text/plain" :
http://www.expita.com/nomime.html : to 10K bytes :

[Pedro Graca]

Sorby wrote:

Here is an exact cut'n'paste of the bit I want to replace.

<a href="/1/files/small/north/page2.htm"><img height="120" hspace="0"
align="left" vspace="0" border="0" width="80" alt="original photo"
src="http://www.mysite.com/origpic.jpg" /></a>

Hmmmm ... and you want to change just the URL and image SRC ?

<a href="========= == CHANGED =========="><im g height="120" hspace="0"
align="left" vspace="0" border="0" width="80" alt="original photo"
src="========== ==== CHANGED ==========" /></a>

Copy the stuff that you want to keep to the regexp and for the stuff you
want replaced use
[^"]+
which means: one or more of anything except quotes

so

$regexp = '@' .
'<a href="[^"]+"><img height="120" hspace="0" ' .
## =URL=
'align="left" vspace="0" border="0" width="80" alt="original photo" ' .
'src="[^"]+" /></a>' .
## =SRC=
'@';

$destin = preg_replace($r egexp, $newlink, $source);
--
USENET would be a better place if everybody read: : mail address :
http://www.catb.org/~esr/faqs/smart-questions.html : is valid for :
http://www.netmeister.org/news/learn2quote2.html : "text/plain" :
http://www.expita.com/nomime.html : to 10K bytes :