I am trying to use the std::accumulate function. When I compile the
following code I get: error C2780: '_Ty
std::accumulate (_InIt,_InIt,_T y,_Fn2)' : expects 4 arguments - 3 provided.
It should accept three inputs as I've used below. I don't understand. I'd
really appreciate it if someone could set me straight. I've looked at the
declaration in numeric, there is a three input template as I've used. Also
in the help files included with MS VC++ there is an example as I've used the
function. I don't get it! Thanks in advance for any time and help you can
provide. I am using MS VC++ Version 7.1.3088 with .NET Framework ver.
1.1.4322 SP1
#include <iostream>
#include <numeric>
#include <list>
using namespace std;
double average(const list<double>&);
int main(){
list<double> lInput;
double dInput;
while(cin >> dInput){
lInput.push_bac k(dInput);
cout << "Average so far: " << average(lInput) << endl;
}
return 0;
}
double average(const list<double>& l){
return accumulate(l.be gin(), l.end, 0.0) / l.size();
} 2 1181
double average(const list<double>& l){
return accumulate(l.be gin(), l.end, 0.0) / l.size(); //Error: missed params
}
Must be
double average(const list<double>& l){
return accumulate(l.be gin(), l.end(), 0.0) / l.size();
}
--
Un saludo
Rodrigo Corral González [MVP]
FAQ de microsoft.publi c.es.vc++ http://rcorral.mvps.org
Thank you very much. I stared at the code, looked at examples, looked on the
web, etc. The answer was very obvious, but I just didn't see it. Thank you
for your reply and your time.
Saludos,
Ben R
"Rodrigo Corral [MVP]" wrote: double average(const list<double>& l){ return accumulate(l.be gin(), l.end, 0.0) / l.size(); //Error: missed params }
Must be
double average(const list<double>& l){ return accumulate(l.be gin(), l.end(), 0.0) / l.size(); }
-- Un saludo Rodrigo Corral González [MVP]
FAQ de microsoft.publi c.es.vc++ http://rcorral.mvps.org This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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