why won't the following work
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
basically I am trying to create a numer of placeholders with thier
associated imgages!
thanks in advance
stuart 33  3749 
> why won't the following work
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
Where did you get this code?
Douglas Crockford <no****@laserli nk.net> wrote in message
news:55******** *************** ****@msgid.mega newsservers.com ... why won't the following work
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
Where did you get this code?
It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable
I need to create a variable amount of placeholders and cache images such as
img1 = new Image(100,200)
img1.src = 'someURL'
img2 = new Image(100,200)
img2.src = 'someURL'
img3 = new Image(100,200)
img3.src = 'someURL'
I am trying to construct the placeholder through a loop as folows
for(var i=1;i<pics;i++) {
( img + i ) = new Image(100,200)
(img + i).src = 'someURL'
}
what I don't know is how to join img and i
Stuart wrote: why won't the following work
Because it's evil[tm] eval(...). Besides, you are neither telling what you
are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value to
their `src' property, so I consider it working.
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
basically I am trying to create a numer of placeholders with thier
associated imgages!
Provided that `pics' stores the number of Image objects to create, that
`wth' and `hgt' are values for the width and height of *each* object and
that the image resources to be accessed are available via the URLs http://www.mypics/X1.gif, where X is a number from 0 to pics - 1, use
var myImages = new Object();
for (var i = 0; i < pics; i++)
{
myImages['img' + i] = new Image(wth, hgt);
myImages['img' + i].src = 'http://www.mypics/' + i + '1.gif';
}
instead.
PointedEars
> > > why won't the following work
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
Where did you get this code?
It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable
Who told you to use eval()?
Thomas 'PointedEars' Lahn wrote: Stuart wrote: why won't the following work
Because it's evil[tm] eval(...). Besides, you are neither telling what you
are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value to
their `src' property, so I consider it working.
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
Hm, having tested it in Mozilla 1.5b and IE 6.0 SP-1, I'm getting a script
error because eval(...) isn't allowed as left-hand side expression (IE says
explicitely: "Cannot assign to a result of a function" (or similar,
translated it from German). Maybe I'm mixing up something here, but I
remember ECMAScript implementations where it was possible to use it there.
However, it's still bad style.
PointedEars
Douglas Crockford <no****@laserli nk.net> wrote in message
news:8a******** *************** ***@msgid.megan ewsservers.com. .. > why won't the following work
>
> for(var i=0;i<pics;i++) {
> eval('img'+i) = new Image(wth,hgt)
> eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
> }
Where did you get this code?
It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable
Who told you to use eval()?
I am trying anything....inc luding asking you!
Are you getting the jist of what I am trying to achieve?
Thomas 'PointedEars' Lahn <Po*********@we b.de> wrote in message
news:bo******** *****@ID-107532.news.uni-berlin.de... Thomas 'PointedEars' Lahn wrote:
Stuart wrote: why won't the following work
Because it's evil[tm] eval(...). Besides, you are neither telling what
you are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value
to their `src' property, so I consider it working.
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}
Hm, having tested it in Mozilla 1.5b and IE 6.0 SP-1, I'm getting a script
error because eval(...) isn't allowed as left-hand side expression (IE
says explicitely: "Cannot assign to a result of a function" (or similar,
translated it from German). Maybe I'm mixing up something here, but I
remember ECMAScript implementations where it was possible to use it there.
However, it's still bad style.
Yes, I am getting these exact same errors,. However, I am pleased you
understood what I am trying to do, May be it is "bad style" but I am new to
javaScript, so may be you could point me in the way of "Good Style" and the
correct way of scripting.
Stuart said:
Douglas Crockford <no****@laserli nk.net> wrote in message
news:55******* *************** *****@msgid.meg anewsservers.co m... > why won't the following work
>
> for(var i=0;i<pics;i++) {
> eval('img'+i) = new Image(wth,hgt)
> eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
> }
Where did you get this code?
It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable
I need to create a variable amount of placeholders and cache images such as
img1 = new Image(100,200)
img1.src = 'someURL'
img2 = new Image(100,200)
img2.src = 'someURL'
img3 = new Image(100,200)
img3.src = 'someURL'
I am trying to construct the placeholder through a loop as folows
for(var i=1;i<pics;i++) {
( img + i ) = new Image(100,200)
(img + i).src = 'someURL'
}
what I don't know is how to join img and i
Whenever you find yourself using eval(), you've probably
overlooked a simpler way to do something.
var img=new Array();
for(var i=0;i<pics;i++) {
img[i] = new Image(100,200);
img[i].src = 'someURL';
}
> > Who told you to use eval()?
I am trying anything....inc luding asking you!
Are you getting the jist of what I am trying to achieve?
It is almost always extremely wrong to use eval(). Who is teaching you to
program so badly? This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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