eval

[Stuart]

why won't the following work

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

basically I am trying to create a numer of placeholders with thier
associated imgages!

thanks in advance
stuart

[Douglas Crockford]

> why won't the following work

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

Where did you get this code?

[Stuart]

Douglas Crockford <no****@laserli nk.net> wrote in message
news:55******** *************** ****@msgid.mega newsservers.com ...

why won't the following work

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

Where did you get this code?

It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable

I need to create a variable amount of placeholders and cache images such as

img1 = new Image(100,200)
img1.src = 'someURL'
img2 = new Image(100,200)
img2.src = 'someURL'
img3 = new Image(100,200)
img3.src = 'someURL'

I am trying to construct the placeholder through a loop as folows

for(var i=1;i<pics;i++) {
( img + i ) = new Image(100,200)
(img + i).src = 'someURL'
}

what I don't know is how to join img and i

[Thomas 'PointedEars' Lahn]

Stuart wrote:

why won't the following work
Because it's evil[tm] eval(...). Besides, you are neither telling what you
are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value to
their `src' property, so I consider it working.
for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

basically I am trying to create a numer of placeholders with thier
associated imgages!

Provided that `pics' stores the number of Image objects to create, that
`wth' and `hgt' are values for the width and height of *each* object and
that the image resources to be accessed are available via the URLs
http://www.mypics/X1.gif, where X is a number from 0 to pics - 1, use

var myImages = new Object();
for (var i = 0; i < pics; i++)
{
myImages['img' + i] = new Image(wth, hgt);
myImages['img' + i].src = 'http://www.mypics/' + i + '1.gif';
}

instead.
PointedEars

[Douglas Crockford]

> > > why won't the following work

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

Where did you get this code?

It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable

Who told you to use eval()?

[Thomas 'PointedEars' Lahn]

Thomas 'PointedEars' Lahn wrote:

Stuart wrote:

why won't the following work

Because it's evil[tm] eval(...). Besides, you are neither telling what you
are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value to
their `src' property, so I consider it working.

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

Hm, having tested it in Mozilla 1.5b and IE 6.0 SP-1, I'm getting a script
error because eval(...) isn't allowed as left-hand side expression (IE says
explicitely: "Cannot assign to a result of a function" (or similar,
translated it from German). Maybe I'm mixing up something here, but I
remember ECMAScript implementations where it was possible to use it there.
However, it's still bad style.
PointedEars

[Stuart]

Douglas Crockford <no****@laserli nk.net> wrote in message
news:8a******** *************** ***@msgid.megan ewsservers.com. ..

> why won't the following work
>
> for(var i=0;i<pics;i++) {
> eval('img'+i) = new Image(wth,hgt)
> eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
> }

Where did you get this code?

It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable

Who told you to use eval()?

I am trying anything....inc luding asking you!
Are you getting the jist of what I am trying to achieve?

[Stuart]

Thomas 'PointedEars' Lahn <Po*********@we b.de> wrote in message
news:bo******** *****@ID-107532.news.uni-berlin.de...

Thomas 'PointedEars' Lahn wrote:

Stuart wrote:

why won't the following work
Because it's evil[tm] eval(...). Besides, you are neither telling what you are consider working nor what `pics' aso. are. Nevertheless, despite its
bad style, the below code does create Image objects and assigns a value to their `src' property, so I consider it working.

for(var i=0;i<pics;i++) {
eval('img'+i) = new Image(wth,hgt)
eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
}

Hm, having tested it in Mozilla 1.5b and IE 6.0 SP-1, I'm getting a script
error because eval(...) isn't allowed as left-hand side expression (IE

says explicitely: "Cannot assign to a result of a function" (or similar,
translated it from German). Maybe I'm mixing up something here, but I
remember ECMAScript implementations where it was possible to use it there.
However, it's still bad style.

Yes, I am getting these exact same errors,. However, I am pleased you
understood what I am trying to do, May be it is "bad style" but I am new to
javaScript, so may be you could point me in the way of "Good Style" and the
correct way of scripting.

[Lee]

Stuart said:

Douglas Crockford <no****@laserli nk.net> wrote in message
news:55******* *************** *****@msgid.meg anewsservers.co m...

> why won't the following work
>
> for(var i=0;i<pics;i++) {
> eval('img'+i) = new Image(wth,hgt)
> eval('img'+i+'. src') = 'http://www.mypics/'+i+'1.gif'
> }

Where did you get this code?

It is part of a bigger script that I am writting, the problem that I am
facing is that I cannot asign the src value to a constucted variable

I need to create a variable amount of placeholders and cache images such as

img1 = new Image(100,200)
img1.src = 'someURL'
img2 = new Image(100,200)
img2.src = 'someURL'
img3 = new Image(100,200)
img3.src = 'someURL'

I am trying to construct the placeholder through a loop as folows

for(var i=1;i<pics;i++) {
( img + i ) = new Image(100,200)
(img + i).src = 'someURL'
}

what I don't know is how to join img and i

Whenever you find yourself using eval(), you've probably
overlooked a simpler way to do something.

var img=new Array();
for(var i=0;i<pics;i++) {
img[i] = new Image(100,200);
img[i].src = 'someURL';
}

[Douglas Crockford]

> > Who told you to use eval()?

I am trying anything....inc luding asking you!
Are you getting the jist of what I am trying to achieve?

It is almost always extremely wrong to use eval(). Who is teaching you to
program so badly?