Error: Unknown runtime error in ie while using ajax

[vjayis]

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

[HTML]<script type="text/javascript">
var id;
var action;
function httprequest(id, action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onready statechange=fun ction()
{
if(xmlhttp.read yState==4)
{
document.getEle mentById("ajax" ).innerHTML=xml http.responseTe xt;
}
}

xmlhttp.open("G ET","url/"ajax.php?id="+ id+"&action="+a ction,true);
xmlhttp.send(nu ll);
}

function hidden(id,actio n)
{
httprequest(id, action)
}
</script>

<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>
[/HTML]

Could anyone help me.,
Thanks.,
vijay

[vjayis]

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

[HTML]<script type="text/javascript">
var id;
var action;
function httprequest(id, action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onready statechange=fun ction()
{
if(xmlhttp.read yState==4)
{
document.getEle mentById("ajax" ).innerHTML=xml http.responseTe xt;
}
}

xmlhttp.open("G ET","url/"ajax.php?id="+ id+"&action="+a ction,true);
xmlhttp.send(nu ll);
}

function hidden(id,actio n)
{
httprequest(id, action)
}
</script>


<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>


[/HTML]
Could anyone help me.,
Thanks.,
vijay

[vjayis]

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

<script type="text/javascript">
var id;
var action;
function httprequest(id,action)
{
 
var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest();
}
catch(e)
{
try
{
xmlhttp=new Activexobject("Msxml2.XMLHTTP");
}
catch(e)
{
try
{
xmlhttp=new Activexobject("MICROSOFT.XMLHTTP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}
 
}
xmlhttp.onreadystatechange=function()
{
if(xmlhttp.readyState==4)
{
document.getElementById("ajax").innerHTML=xmlhttp.responseText;
}
}
 
xmlhttp.open("GET","url/"ajax.php?id="+id+"&action="+action,true);
xmlhttp.send(null);
}
 
function hidden(id,action)
{
httprequest(id,action)
}
</script>
 
 
<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden('1','next')">next</a></td></tr>
</table>

Could anyone help me.,
Thanks.,
vijay

[rpnew]

hi
when i m trying to fetch data from one page to another page using ajax, i get an error message in IE., but it runs well in firefox., could anyone help me.,

here is my javascript code.,

<script type="text/javascript">
var id;
var action;
function httprequest(id, action)
{

var xmlhttp;
try
{
xmlhttp=new XMLHttpRequest( );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" Msxml2.XMLHTTP" );
}
catch(e)
{
try
{
xmlhttp=new Activexobject(" MICROSOFT.XMLHT TP")
}
catch(e)
{
alert("ur browser doesnot support Ajax");
return false;
}
}

}
xmlhttp.onready statechange=fun ction()
{
if(xmlhttp.read yState==4)
{
document.getEle mentById("ajax" ).innerHTML=xml http.responseTe xt;
}
}

xmlhttp.open("G ET","url/"ajax.php?id="+ id+"&action="+a ction,true);
xmlhttp.send(nu ll);
}

function hidden(id,actio n)
{
httprequest(id, action)
}
</script>


<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>



Could anyone help me.,
Thanks.,
vijay

Hi,

What is the error that you are getting??

Regards,
RP

[ronverdonk]

Please enclose your posted code in [code] tags (See How to Ask a Question).

This makes it easier for our Experts to read and understand it. Failing to do so creates extra work for the moderators, thus wasting resources, otherwise available to answer the members' questions.

Please use [code] tags in future.

This is not a PHP question, but a JavaScript one.

This thread will be moved to the JS forum.

moderator

[hsriat]

xmlhttp.open("GET", "ajax.php?id=" + id + "&action=" + action, true);

[acoder]

Threads merged. Please do not double post your questions.

Moderator.

[vjayis]

Hi,

What is the error that you are getting??

Regards,
RP

hi Rp.,

when i click on the ajax link("Next") i get an error displaying tht:
Error: Unknown runtime error;

thts it.,

thanks.,
vijay

[acoder]

You have an extra double quote in the URL string:

"url/"ajax.php?id="+id+"&action="+action

instead of

"url/ajax.php?id="+id+"&action="+action

[vjayis]

You have an extra double quote in the URL string:

"url/"ajax.php?id="+id+"&action="+action

instead of

"url/ajax.php?id="+id+"&action="+action

hi

sorry for the mistake.,

i hav written

"url/ajax.php?id="+id+"&action="+action

[/quote] like this only.,

instead of giving the full link i just typed it inside the quoutes to replace my web link., just to highlight the link.,

I replace my full code one more time.,

<script type="text/javascript">
var id;
var action;
function httprequest(id,action)
{
 
var xmlhttp;
try
{
 xmlhttp=new XMLHttpRequest();
}
catch(e)
{
  try
  {
  xmlhttp=new Activexobject("Msxml2.XMLHTTP");
  }
  catch(e)
  { 
    try
    {
    xmlhttp=new Activexobject("MICROSOFT.XMLHTTP")
    }
    catch(e)
    {
     alert("ur browser doesnot support Ajax");
     return false;
    }
  }
 
}
xmlhttp.onreadystatechange=function()
{ 
 if(xmlhttp.readyState==4)
 { 
 
   obj = document.getElementById( "ajax" );
 
   obj.innerHTML = xmlhttp.responseText;
   getBufferText();
 
 }
}
 
xmlhttp.open("GET", "url/ajax.php?id=" + id + "&action=" + action, true);
xmlhttp.send(null);
}
 
function hidden(id,action)
{
 httprequest(id,action)
}
</script>
 

[code-php]

<table id="ajax">------Place where i fetch data from another page and display---------
<tr><td><a onclick="hidden ('1','next')">n ext</a></td></tr>
</table>

[/code]
thanks