space trouble......

[shweta khare]

basically we observed that in order to input 2 character constants at a time we
ought to give spaces....hav a peek in ter dis....
case1

void main( )
{
char a,b;
printf("\n enter 2 characters");
scanf("%c%c",&a ,&b);
printf("\n %c %c ",a,b);
getch( );
}

now the program executes in the following way-it will only take one character as an input and print the same



case2

provided the entire program remains the same and u only introduce spaces in satement no3- scanf("%c %c",&a,&b);
now it takes 2 characters as input and prints both of them



case3

provided the entire program remains the same and we only cahange the 3rd statement ie scanf("%c %c ");note that here we have given a space after the 2nd %c as well...in this case the compiler waits for three characters to be entered b4 printing the output ie the 1st two characters...


there is a vast variation in the execution of the program jst bcoz of the spaces....y does this happen?...

[Banfa]

case1

void main( )
{
char a,b;
printf("\n enter 2 characters");
scanf("%c%c",&a ,&b);
printf("\n %c %c ",a,b);
getch( );
}

now the program executes in the following way-it will only take one character as an input and print the same

That is not the behaviour I observe, I input 2 characters for this case and it outputs 2 characters.

Program Output

enter 2 charactersab

a b Press any key to continue . . .

If you are pressing return after the first letter you get

enter 2 charactersa

a
Press any key to continue . . .

This is still outputing 2 characters, the 2 characters entered are 'a' and '\n' note the 'Press any key to continue . . .' is on the line below the a this time, the program has read 'a' and '\n' and then output 'a' and '\n' you are just failing to notice it because it is not a printable character.

[shweta khare]

thank u for clarifying my doubts...