getting signal SEGV in my small program

[rasmidas]

I have written a file as below:

#include<stdio. h>
#include<string .h>
#include<stdlib .h>
int main()
{
char* items[2];
int i;
for(i=0;i<2;i++ )
{
char* temp = new char[11];
strcpy(temp,"AB CD EFGH");
items[i] = temp;
printf("items is:%u=%u\n",&it ems[i],items[i]);
printf("items is:%s\n",*temp) ;
}
printf("\n\nite ms is:%u\n",items) ;
printf("\nitems is:%u\n",&items );
items[2] = 0;
char** item_ptr = items;
while (*item_ptr != 0)
{
printf("item_pt r is:%u\n",*item_ ptr);
printf("item_pt r is:%u\n",**item _ptr);
printf("item_pt r is:%u\n",item_p tr);
printf("item_pt r is:%d\n",item_p tr);
item_ptr++;
}
return 0;
}

While I am compiling it, it gives segmentation fault:
Here I am pasting

(L)SUMV3/sparse/src/stk/dmg_meta_doc$ gcc ras1.cc
(L)SUMV3/sparse/src/stk/dmg_meta_doc$ ./a.out
items is:4026512392=1 65408
Segmentation Fault

Now I tried to debug that using dbx which is as below:

(L)SUMV3/sparse/src/stk/dmg_meta_doc$ dbx a.out
changes (topic)
The major new features of this release relative to 6.0 are:

o The dbx environment variable "cfront_demangl ing" has been removed.
The "-F" option to dbx (allow cfront-demangling) has also been removed.
Use an earlier version of dbx to get cfront support.
o This release continues to support Fortran intrinsics on Intel, even
though the Intel Fortran compiler was not shipped with WorkShop 6.
The next dbx release will not support Fortran intrinsics on Intel.

See also `help changes60'


To suppress this message, add the following line to your .dbxrc file:

dbxenv suppress_startu p_message 5.0
Reading a.out
dbx: warning: cannot demangle '__10bad_typeid '
dbx: warning: cannot demangle '__13bad_except ion'
dbx: warning: cannot demangle '__14__si_type_ infoPCcRC16__us er_type_info'
dbx: warning: cannot demangle '__16__user_typ e_infoPCc'
dbx: warning: cannot demangle '__17__class_ty pe_infoPCcPCQ21 7__class_type_i nfo9base_infoUi '
Reading ld.so.1
Reading libc.so.1
Reading libdl.so.1
Reading libc_psr.so.1
(dbx) where
dbx: program is not active
(dbx) run
Running: a.out
(process id 23331)
items is:4026512168=1 65408
signal SEGV (no mapping at the fault address) in strlen at 0xef6a53e4
0xef6a53e4: strlen+0x001c: ldub [%o1], %o3
(dbx) where
dbx: program is not active
(dbx) run
Running: a.out
(process id 23331)
items is:4026512168=1 65408
signal SEGV (no mapping at the fault address) in strlen at 0xef6a53e4
0xef6a53e4: strlen+0x001c: ldub [%o1], %o3
(dbx) where
=>[1] strlen(0x0, 0x41, 0x0, 0x1, 0x3a, 0xef72c8ac), at 0xef6a53e4
[2] _doprnt(0x16ceb , 0x0, 0x0, 0x41, 0x0, 0x0), at 0xef6dc834
[3] printf(0x16ce0, 0xef72d134, 0xef725930, 0xefffb328, 0x16c00, 0xef698ea8), at 0xef6e5990
[4] main(0x1, 0xefffb3a4, 0xefffb3ac, 0x28518, 0x0, 0x0), at 0x12538
(dbx) quit

Here it is showing that the error is in the function strlen. Which I didnot use. Rather I used strcpy().

Please let me know what is wrong in my program and how I will print the string
"AB CD EFGH".
Thanks in advance.

[JosAH]

char* temp = new char[11];
strcpy(temp,"AB CD EFGH");
printf("items is:%s\n",*temp) ;

This is definitely wrong; temp is a char* (a pointer to a char) so *temp is a char
and you can't treat it as if it were a char* (%s)

kind regards,

Jos

pa. the SIG_SEGV occurs during *runtime*, not during *compile* time.

[rasmidas]

So, can I write that as below:

char* temp = new char[11];
char buffer[11]="AB CD EFGH";
strcpy(temp,buf fer);

Please suggest me. Thanks.

[JosAH]

So, can I write that as below:

char* temp = new char[11];
char buffer[11]="AB CD EFGH";
strcpy(temp,buf fer);

Please suggest me. Thanks.

That's not needed; it the following line that is wrong:

printf("items is:%s\n",*temp);
 

Make it read like this:

printf("items is:%s\n",temp);
 

kind regards,

Jos

[rasmidas]

One more question, In my program while debugging why
it is showing that the error is in the function strlen(). Which I didnot use. Rather I used strcpy(). Thanks.

[JosAH]

One more question, In my program while debugging why
it is showing that the error is in the function strlen(). Which I didnot use. Rather I used strcpy(). Thanks.

Maybe you didn't call that function, but most likely the printf() function called it.

kind regards,

Jos