What does this code do?

[locy]

can someone explain to me "what does this code do"

class baseclass
{ 
   public:
   virtual void runme()
   {
    std::cout<<"are you"<<std::endl;
   }
};
class derivedclass :public bassclass
{
   public:
   void runme()
   {
    std::cout<<"there"<<std::endl;
   }
}
baseclass  *test_class =new Derivedclass();
test_class->runme();
 

does the code surpose to read out.
"are you there"

[weaknessforcats]

The output is: there

Your object is a derivedclass object. This object has a virtual function table (VTBL) with the addresses of all virtual functions declared in the class or inherited. The derivedclass::r unme() method has overriden baseclass::runm e() so it is the address of derivedclass::r unme() in the VTBL.

Therefor, it is derivedclass::r unme() that is called when you use the derivedclass object with a baseclass pointer or reference.

This is basic polymorphism. A program using polymorphism is an object-oriented program.