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Dynamic arrays

Hi,

I'm trying to use a dynamic array but for some reason it won't work. This is
my code :

int *test;
int numElements = 2;

test = (int *) malloc (numElements * sizeof(int));
if (test= NULL) printf("Can't allocate\n"); // Nothing happens here
so it's ok I guess
test[0] = 10; // <- CRASH!
printf( "test= %d\n",test[0] );

I copied it from the internet and it seems that they all do it this way?
Then why won't this work? My computer sure has enough for 2 integers...

Greetings,
Rick
Nov 13 '05
20 12808
Rick wrote:

Wait! I talk too fast. It does work now,
after including #include <stdlib.h> as well.


#include <stdlib.h>, is part of the program code.

When you post code to this newsgroup,
try to post the smallest complete entire program
which exhibits your problem.

--
pete
Nov 13 '05 #21

This thread has been closed and replies have been disabled. Please start a new discussion.

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