for(x = 0; x < 9; x++) when is x incremented?

[John Smith]

Why in the printout of the following code s, t, and u only go up
to 9 but w and x 10? I would think they would at least go up to
the same number, be it 9 or 10.

The last line of the printout is:

column 9 row 9 u 9 v 0 w 10 x 10 y 1 z 48652
-----------------------------------------
for(s = 0; s < 9; s++)
for(t = 0; t < 9; t++)
for(u = 0; u < 9; u++)
{
if(v = Cell[s][t].GetElement(u) != 0)
for(w = 0; w < 9; w++)
{
if(w != t)
{
for(x = 0; x < 9; x++)
{
if(y = Cell[s][w].GetElement(x) != 0)
if(v >= y)
if( v == y)
{
z++;
}
}
}
}
cout << "column " << s+1 << " row " << t+1 << \\
" u " << u+1 << " v " << v << " w " << w+1 << " x " << x+1 \\
<< " y " << y << " z " << z << '\n';
}

[John Carson]

"John Smith" <js****@company .com> wrote in message
news:VE******** **********@twis ter.southeast.r r.com

Why in the printout of the following code s, t, and u only go up
to 9 but w and x 10? I would think they would at least go up to
the same number, be it 9 or 10.

Incrementation takes place after the body of the for() loop is executed. In
your case, the printout occurs after the body of the w and x for loops but
inside the body of the s, t and u loops. That explains the difference.

--
John Carson

[Otac0n]

The basic "unrolled" (missused, i know) form of a for-loop is:

for( statement; conditional; operation )
{
body;
}

becomes

statement;
while( conditional )
{
body;
operation;
}

and can, in fact, replace all while-loops (but for clarity, while-loops
are still viable)

[guyarad]

and you should see any 10s if the condition is "x<9".
The reason is simple - when outputting he sometime print out x+1 and
sometie just 'v'...

None of the variables reaches 10....

[paulius-maruska]

Actualy, none of the variables reaches 9, because conditions in all
cases are "x<9", when variable reaches 9 - loop body isn't executed
anymore.
gu*****@gmail.c om raše:

and you should see any 10s if the condition is "x<9".
The reason is simple - when outputting he sometime print out x+1 and
sometie just 'v'...

None of the variables reaches 10....

[guyarad]

you are wrong.
see that when the condition of the loop is evaluated (x<9) and the body
than skipped, x is already 9! otherwise the body of the loop will be
executed.

when you have something like this:
for (int i=0; i<9; i++) {
/// bla.... some statements
}
cout << i;
the output will always (if the loop was not ended abruptly) be '9'.

[guyarad]

I'm sorry, I think I misunderstood you.
I guess you meant '9' is never PRINTED - but you wrote "none of the
variables reaches 9".
But also this is not accurate, because w does reaches 9 in before the
cout command is reached.

[Vimal Aravindashan]

gu*****@gmail.c om wrote:

you are wrong.
see that when the condition of the loop is evaluated (x<9) and the body
than skipped, x is already 9! otherwise the body of the loop will be
executed.

when you have something like this:
for (int i=0; i<9; i++) {
/// bla.... some statements
}
cout << i;
the output will always (if the loop was not ended abruptly) be '9'.

Please quote the messages in your replies. Use the 'Reply' in the 'More
options' link if you are using the google-groups interface.

And, in
for(int i.....) { }
the scope of 'i' is restricted to within the for loop, it is not visible
outside. :-)

Cheers,
Vimal.
--
"If you would be a real seeker after truth, it is necessary that at
least once in your life you doubt, as far as possible, all things."
-- Rene Descartes