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Remove/omit duplicate records in MS Access Query result

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This is the SQL code for starters.
Expand|Select|Wrap|Line Numbers
  1. SELECT DISTINCTROW [Qry_CRM_MNGT_150+_No_Action_NEW].CYCLE_DATE, [Qry_CRM_MNGT_150+_No_Action_NEW].SERIES_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_NAME, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].INTERNAL_LOAN_ID, [Qry_CRM_MNGT_150+_No_Action_NEW].ARCC_LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].LIEN_STATUS_CODE, [Qry_CRM_MNGT_150+_No_Action_NEW].MaxOfACTL_END_PRIN_BAL, [Qry_CRM_MNGT_150+_No_Action_NEW].REPORTED_ACTION_CODE, [Qry_CRM_MNGT_150+_No_Action_NEW].MONTHS_DELQ, IIf([COMMENT_CODE]="CX",[COMMENT_DATE_TIME],"") AS NEW_COMMENT_DATE_TIME, (IIf([COMMENT_CODE]="CX",[STAFF_NAME],"")) AS NEW_STAFF_NAME, (IIf([COMMENT_CODE]="CX",[COMMENT_TEXT],"")) AS NEW_COMMENT_TEXT, (IIf([COMMENT_CODE]="CX","CX","")) AS NEW_COMMENT_CODE
  2. FROM ([Qry_CRM_MNGT_150+_No_Action_NEW] LEFT JOIN MARS_COMMENTS_INFO ON [Qry_CRM_MNGT_150+_No_Action_NEW].INTERNAL_LOAN_ID = MARS_COMMENTS_INFO.INTERNAL_LOAN_ID) LEFT JOIN MARS_IFS_STAFF_INFO ON MARS_COMMENTS_INFO.COMMENT_AUTHOR = MARS_IFS_STAFF_INFO.INTERNAL_STAFF_LOGON
  3. GROUP BY [Qry_CRM_MNGT_150+_No_Action_NEW].CYCLE_DATE, [Qry_CRM_MNGT_150+_No_Action_NEW].SERIES_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_NAME, [Qry_CRM_MNGT_150+_No_Action_NEW].SERVICER_LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].INTERNAL_LOAN_ID, [Qry_CRM_MNGT_150+_No_Action_NEW].ARCC_LOAN_NBR, [Qry_CRM_MNGT_150+_No_Action_NEW].LIEN_STATUS_CODE, [Qry_CRM_MNGT_150+_No_Action_NEW].MaxOfACTL_END_PRIN_BAL, [Qry_CRM_MNGT_150+_No_Action_NEW].REPORTED_ACTION_CODE, [Qry_CRM_MNGT_150+_No_Action_NEW].MONTHS_DELQ, IIf([COMMENT_CODE]="CX",[COMMENT_DATE_TIME],""), (IIf([COMMENT_CODE]="CX",[STAFF_NAME],"")), (IIf([COMMENT_CODE]="CX",[COMMENT_TEXT],"")), (IIf([COMMENT_CODE]="CX","CX","")); 



The purpose of this query is to identify the records that meet the specified parameters, with it's respective comment (s)if there is(are) any, and also the those records that have no comment (null) but meet the parameters. The problem I have is that for records that have a comment(s), and additional record shows up in the results with null comment value.

I am trying to figure out how I can eliminate the duplicate record with the Null comment value if that same record has a comment already showing in the results.
Oct 16 '08 #1
1 4887
nico5038
3,080 Recognized Expert Specialist
Looks to me you can have multiple comments.
If that's the case and one has a code <> CX it will add an empty row.

One solution is to use a groupby query to filter the comments (MARS_COMMENTS_ INFO) for "CX" and select the comment of the MAX(COMMENT_DAT E_TIME). (So first a groupby on INTERNAL_LOAN_I D with the MAX(COMMENT_DAT E_TIME) for the "CX" comments and that query JOINED by INTERNAL_LOAN_I D and MAX(COMMENT_DAT E_TIME) to get the (single) "CX" comment.
When the COMMENT_DATE_TI ME is unique this will work, otherwise I would add also a MAX(COMMENT_TEX T).

Getting the idea ?

Nic;o)
Oct 24 '08 #2

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