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How to check the address for an external module library

Dear reader,

In case an application is ussing an external model library you have to
address this external model library in your application.

This addressing takes place in a module of the application by opening of a
module and activates [Tools] [References...] and than brows to the location
of the external library.

For my applications I store these libraries in the same folder as the
application.

And know my question pops up because if I replace the application including
the external library into an other folder the addressing to the external
library will be lost. You have to address your external library again.

Is there same code available for the application to check the connection to
an external library and reconnect them if this connection is broken?

Thanks for any help.

Kind regards,

Simon van Beek
Nov 13 '05 #1
1 1992
On Tue, 24 May 2005 08:26:01 +0200, "S. van Beek" <S.******@HCCne t.nl>
wrote:

You can iterate over the References collection, and check for
IsBroken.
Or you could install your library in the Windows System folder, like
most everyone else does.

-Tom.

Dear reader,

In case an application is ussing an external model library you have to
address this external model library in your application.

This addressing takes place in a module of the application by opening of a
module and activates [Tools] [References...] and than brows to the location
of the external library.

For my applications I store these libraries in the same folder as the
application.

And know my question pops up because if I replace the application including
the external library into an other folder the addressing to the external
library will be lost. You have to address your external library again.

Is there same code available for the application to check the connection to
an external library and reconnect them if this connection is broken?

Thanks for any help.

Kind regards,

Simon van Beek


Nov 13 '05 #2

This thread has been closed and replies have been disabled. Please start a new discussion.

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