I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.Output Stream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
2  1395 
On Aug 3, 11:46 am, AY Xu <ay...@yahoo.co mwrote:
I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.Output Stream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
If i understood correclty,
System.Diagnost ics.Process.Sta rt http://msdn.microsoft.com/en-us/libr...ess.start.aspx
Sure, if necessary applications have been associated with proper file
types like Ms Word for *.doc extensions already.
Hope this helps,
Onur Güzel
On 8ÔÂ3ÈÕ, ÏÂÎç5ʱ19·Ö, kimiraikkonen <kimiraikkone.. ..@gmail.comwro te:
On Aug 3, 11:46 am, AY Xu <ay...@yahoo.co mwrote:
I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.Output Stream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
If i understood correclty,
System.Diagnost ics.Process.Sta rthttp://msdn.microsoft. com/en-us/library/system.diagnost ics.process.st. ..
Sure, if necessary applications have been associated with proper file
types like Ms Word for *.doc extensions already.
Hope this helps,
Onur G¨¹zel
Great, you point me to the right direction! i just set the file name,
then process.start() , .net automatically start right program to open
the file. that's great! thanks for help! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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