I found this statement in some sample code. It seems to be syntactically
correct. What do the brackets around "String" mean?
Dim sWork As [String] = "Some number of characters"
13  1994 
"Herman Jones" <He*********@di scussions.micro soft.comwrote in message
news:6F******** *************** ***********@mic rosoft.com...
>I found this statement in some sample code. It seems to be syntactically
correct. What do the brackets around "String" mean?
Dim sWork As [String] = "Some number of characters"
They are used indicate the item in the brackets is not a keyword. For
example if you wanted to name a variable Dim you might be able to do this:
Dim [Dim] as Int32
[Dim] = 5
I'm not sure if that works but that the sort of thing it's used for. It
could be used for function names, class names etc. In the case of String
above it does nothing but doesn't cause any problems either. You can remove
them.
Michael
This example seems to be a little different. In your example you're using
[Dim] as a variable name. It comes before the "As" keyword.
The sample code I found has [String] after the "As" keyword. I don't thing
that "String" is being used as the variable name because the program later
refers to the "sWork" variable.
Is it possible that the brackets have some other purpose when they bracket a
datatype?
"Michael C" wrote:
"Herman Jones" <He*********@di scussions.micro soft.comwrote in message
news:6F******** *************** ***********@mic rosoft.com...
I found this statement in some sample code. It seems to be syntactically
correct. What do the brackets around "String" mean?
Dim sWork As [String] = "Some number of characters"
They are used indicate the item in the brackets is not a keyword. For
example if you wanted to name a variable Dim you might be able to do this:
Dim [Dim] as Int32
[Dim] = 5
I'm not sure if that works but that the sort of thing it's used for. It
could be used for function names, class names etc. In the case of String
above it does nothing but doesn't cause any problems either. You can remove
them.
Michael
"Herman Jones" <He*********@di scussions.micro soft.comwrote in message
news:2E******** *************** ***********@mic rosoft.com...
This example seems to be a little different. In your example you're using
[Dim] as a variable name. It comes before the "As" keyword.
The sample code I found has [String] after the "As" keyword. I don't
thing
that "String" is being used as the variable name because the program later
refers to the "sWork" variable.
Is it possible that the brackets have some other purpose when they bracket
a
datatype?
The dim was just 1 example, it can be used in many places. If a program had
a datatype called "As" then you'd need to do Dim x as [As]
Michael
>I found this statement in some sample code. It seems to be syntactically
correct. What do the brackets around "String" mean?
Dim sWork As [String] = "Some number of characters"
That the programmer of this program is probably an idiot.
You replace with this the general meaning of the keyword.
Public Class Form1
Private Sub Form1_Load(ByVa l sender As System.Object, _
ByVal e As System.EventArg s) Handles MyBase.Load
Dim a As New [String](1)
Dim b As String = "What the hell is this"
End Sub
End Class
Public Class [String]
Public Sub New(ByVal b As Integer)
b = b
End Sub
Public b As Integer
End Class
Cor
"Cor Ligthert [MVP]" <no************ @planet.nlwrote in message
news:%2******** ********@TK2MSF TNGP03.phx.gbl. ..
Public Sub New(ByVal b As Integer)
b = b
End Sub
Public b As Integer
Does that actually work in vb.net?
Michael
It runs and gives very strange results.
Cor
"Michael C" <no****@nospam. comschreef in bericht
news:OF******** ******@TK2MSFTN GP02.phx.gbl...
"Cor Ligthert [MVP]" <no************ @planet.nlwrote in message
news:%2******** ********@TK2MSF TNGP03.phx.gbl. ..
> Public Sub New(ByVal b As Integer)
b = b
End Sub
Public b As Integer
Does that actually work in vb.net?
Michael
"Cor Ligthert [MVP]" <no************ @planet.nlwrote in message
news:u%******** ********@TK2MSF TNGP03.phx.gbl. ..
It runs and gives very strange results.
Would it just leave this.b = 0 or uninitialised?
Michael
Try it and find out!
"Michael C" <no****@nospam. comwrote in message
news:%2******** ********@TK2MSF TNGP06.phx.gbl. ..
"Cor Ligthert [MVP]" <no************ @planet.nlwrote in message
news:u%******** ********@TK2MSF TNGP03.phx.gbl. ..
>It runs and gives very strange results.
Would it just leave this.b = 0 or uninitialised?
Michael
zero
"Michael C" <no****@nospam. comschreef in bericht
news:%2******** ********@TK2MSF TNGP06.phx.gbl. ..
"Cor Ligthert [MVP]" <no************ @planet.nlwrote in message
news:u%******** ********@TK2MSF TNGP03.phx.gbl. ..
>It runs and gives very strange results.
Would it just leave this.b = 0 or uninitialised?
Michael
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