How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
6  1513 
Use the EndsWith function of the string. I would recommend not using
anything of the old VB function placed into microsoft.visua lbasic.
What character are you looking for? a period? double quotes?
"Dave" <no****@yahoo.c om> wrote in message
news:Ot******** ********@TK2MSF TNGP12.phx.gbl. .. How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
My rightmost elements are a period followed by a double-quote. I'll check
out that EndsWith function.
"Marina" <so*****@nospam .com> wrote in message
news:%2******** **********@TK2M SFTNGP15.phx.gb l... Use the EndsWith function of the string. I would recommend not using
anything of the old VB function placed into microsoft.visua lbasic.
What character are you looking for? a period? double quotes?
"Dave" <no****@yahoo.c om> wrote in message
news:Ot******** ********@TK2MSF TNGP12.phx.gbl. .. How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so
how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
Ok, so that would be: If myString.EndsWi th(".""") Then
"Dave" <no****@yahoo.c om> wrote in message
news:us******** ********@TK2MSF TNGP10.phx.gbl. .. My rightmost elements are a period followed by a double-quote. I'll check
out that EndsWith function.
"Marina" <so*****@nospam .com> wrote in message
news:%2******** **********@TK2M SFTNGP15.phx.gb l... Use the EndsWith function of the string. I would recommend not using
anything of the old VB function placed into microsoft.visua lbasic.
What character are you looking for? a period? double quotes?
"Dave" <no****@yahoo.c om> wrote in message
news:Ot******** ********@TK2MSF TNGP12.phx.gbl. .. How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so
how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
"Dave" <no****@yahoo.c om> schrieb: My rightmost elements are a period followed by a double-quote. I'll check
out that EndsWith function.
You can encode double quotes inside string literals by two consecutive
double quotes, for example:
\\\
MsgBox("He said: ""Hello world!""")
///
--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>
Dave,
Maybe is this something when you become complete crazy from all those double
quotes
\\\
Dim a As String = """"""""""""""" """"""""""""""" """"""""""" "
Dim b As Integer = 0
For Each chra As Char In a
If chra = Chr(34) Then
b += 1
End If
Next
///
Just as idea
Cor
"Dave" <no****@yahoo.c om> schreef in bericht
news:us******** ********@TK2MSF TNGP10.phx.gbl. .. My rightmost elements are a period followed by a double-quote. I'll check
out that EndsWith function.
"Marina" <so*****@nospam .com> wrote in message
news:%2******** **********@TK2M SFTNGP15.phx.gb l... Use the EndsWith function of the string. I would recommend not using
anything of the old VB function placed into microsoft.visua lbasic.
What character are you looking for? a period? double quotes?
"Dave" <no****@yahoo.c om> wrote in message
news:Ot******** ********@TK2MSF TNGP12.phx.gbl. .. How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so
how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
Why would you recommend not using Microsoft.Visua lbasic functions?
"Marina" wrote: Use the EndsWith function of the string. I would recommend not using
anything of the old VB function placed into microsoft.visua lbasic.
What character are you looking for? a period? double quotes?
"Dave" <no****@yahoo.c om> wrote in message
news:Ot******** ********@TK2MSF TNGP12.phx.gbl. .. How can I determine if the two rightmost elements of my string are ."
?
Obviously, vb.net has a special use for the double-quote character, so how
do I account for that.
I have...
if microsoft.visua lbasic.right(my string, 2) = ??????? Then
I need to know what to put in place of those question marks.
Thanks,
-Dave
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