Hi there,
I'm just starting at VB.NET (all VB come to that), and have what's probably
a very basic question:
I have a form in Visual Studio 2003 that has a listbox that is meant to be
populated with file names from the OpenFileDialog method (see below). The
problem is that if you select, say three files in the Open File dialogue
box, the listbox is populated with three of the same file rather than three
different files.
Any clues on where I'm going wrong?
Many thanks
John
Private Sub button1_Click(B yVal sender As Object, ByVal e As
System.EventArg s) Handles Button1.Click
Dim openFileDialog1 As New OpenFileDialog
Dim fName As String
openFileDialog1 .InitialDirecto ry = "c:\"
openFileDialog1 .Filter = "txt files (*.txt)|*.txt|A ll files (*.*)|*.*"
openFileDialog1 .FilterIndex = 2
openFileDialog1 .RestoreDirecto ry = True
openFileDialog1 .Multiselect = True
If openFileDialog1 .ShowDialog() = DialogResult.OK Then
For Each fName In openFileDialog1 .FileNames
lstWrkFiles.Ite ms.Add(openFile Dialog1.FileNam e)
Next
End If
End Sub 4 17488
John,
In your For Each loop:
lstWrkFiles.Ite ms.Add(fName)
Kerry Moorman
"John" wrote: Hi there,
I'm just starting at VB.NET (all VB come to that), and have what's probably a very basic question:
I have a form in Visual Studio 2003 that has a listbox that is meant to be populated with file names from the OpenFileDialog method (see below). The problem is that if you select, say three files in the Open File dialogue box, the listbox is populated with three of the same file rather than three different files.
Any clues on where I'm going wrong?
Many thanks
John
Private Sub button1_Click(B yVal sender As Object, ByVal e As System.EventArg s) Handles Button1.Click
Dim openFileDialog1 As New OpenFileDialog
Dim fName As String openFileDialog1 .InitialDirecto ry = "c:\"
openFileDialog1 .Filter = "txt files (*.txt)|*.txt|A ll files (*.*)|*.*"
openFileDialog1 .FilterIndex = 2
openFileDialog1 .RestoreDirecto ry = True
openFileDialog1 .Multiselect = True If openFileDialog1 .ShowDialog() = DialogResult.OK Then
For Each fName In openFileDialog1 .FileNames
lstWrkFiles.Ite ms.Add(openFile Dialog1.FileNam e)
Next End If
End Sub
That's great. Thanks very much Kerry.
Seems obvious now you point it out!
John
"Kerry Moorman" <Ke**********@d iscussions.micr osoft.com> wrote in message
news:B9******** *************** ***********@mic rosoft.com... John,
In your For Each loop:
lstWrkFiles.Ite ms.Add(fName)
Kerry Moorman
"John" wrote:
Hi there,
I'm just starting at VB.NET (all VB come to that), and have what's probably a very basic question:
I have a form in Visual Studio 2003 that has a listbox that is meant to be populated with file names from the OpenFileDialog method (see below). The problem is that if you select, say three files in the Open File dialogue box, the listbox is populated with three of the same file rather than three different files.
Any clues on where I'm going wrong?
Many thanks
John
Private Sub button1_Click(B yVal sender As Object, ByVal e As System.EventArg s) Handles Button1.Click
Dim openFileDialog1 As New OpenFileDialog
Dim fName As String openFileDialog1 .InitialDirecto ry = "c:\"
openFileDialog1 .Filter = "txt files (*.txt)|*.txt|A ll files (*.*)|*.*"
openFileDialog1 .FilterIndex = 2
openFileDialog1 .RestoreDirecto ry = True
openFileDialog1 .Multiselect = True If openFileDialog1 .ShowDialog() = DialogResult.OK Then
For Each fName In openFileDialog1 .FileNames
lstWrkFiles.Ite ms.Add(openFile Dialog1.FileNam e)
Next End If
End Sub
John,
In your For Each loop:
lstWrkFiles.Ite ms.Add(fName)
Kerry Moorman
"John" wrote: Hi there,
I'm just starting at VB.NET (all VB come to that), and have what's probably a very basic question:
I have a form in Visual Studio 2003 that has a listbox that is meant to be populated with file names from the OpenFileDialog method (see below). The problem is that if you select, say three files in the Open File dialogue box, the listbox is populated with three of the same file rather than three different files.
Any clues on where I'm going wrong?
Many thanks
John
Private Sub button1_Click(B yVal sender As Object, ByVal e As System.EventArg s) Handles Button1.Click
Dim openFileDialog1 As New OpenFileDialog
Dim fName As String openFileDialog1 .InitialDirecto ry = "c:\"
openFileDialog1 .Filter = "txt files (*.txt)|*.txt|A ll files (*.*)|*.*"
openFileDialog1 .FilterIndex = 2
openFileDialog1 .RestoreDirecto ry = True
openFileDialog1 .Multiselect = True If openFileDialog1 .ShowDialog() = DialogResult.OK Then
For Each fName In openFileDialog1 .FileNames
lstWrkFiles.Ite ms.Add(openFile Dialog1.FileNam e)
Next End If
End Sub
That's great. Thanks very much Kerry.
Seems obvious now you point it out!
John
"Kerry Moorman" <Ke**********@d iscussions.micr osoft.com> wrote in message
news:B9******** *************** ***********@mic rosoft.com... John,
In your For Each loop:
lstWrkFiles.Ite ms.Add(fName)
Kerry Moorman
"John" wrote:
Hi there,
I'm just starting at VB.NET (all VB come to that), and have what's probably a very basic question:
I have a form in Visual Studio 2003 that has a listbox that is meant to be populated with file names from the OpenFileDialog method (see below). The problem is that if you select, say three files in the Open File dialogue box, the listbox is populated with three of the same file rather than three different files.
Any clues on where I'm going wrong?
Many thanks
John
Private Sub button1_Click(B yVal sender As Object, ByVal e As System.EventArg s) Handles Button1.Click
Dim openFileDialog1 As New OpenFileDialog
Dim fName As String openFileDialog1 .InitialDirecto ry = "c:\"
openFileDialog1 .Filter = "txt files (*.txt)|*.txt|A ll files (*.*)|*.*"
openFileDialog1 .FilterIndex = 2
openFileDialog1 .RestoreDirecto ry = True
openFileDialog1 .Multiselect = True If openFileDialog1 .ShowDialog() = DialogResult.OK Then
For Each fName In openFileDialog1 .FileNames
lstWrkFiles.Ite ms.Add(openFile Dialog1.FileNam e)
Next End If
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I'm just starting at VB.NET (all VB come to that), and have what's probably
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I have a form in Visual Studio 2003 that has a listbox that is meant to be
populated with file names from the OpenFileDialog method (see below). The
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