Getting variable in a pattern using Regex

[Ya Ya]

Hi,
I have a string with some fixed text and variable text.
For example: "this is a fixed text THE NEEDED INFO more more fixed text".
How do I get the the variable text (THE NEEDED INFO) from this string ?
A simple example will help.

Thanks.
ra***@hotmail.c om

[Alex Levi]

Dim txt As String
txt = "this is a fixed text THE NEEDED INFO more more fixed text"
txt = Mid(txt, 23, txt.Length - 22)

23 <- starting index
txt.Length - 22 <- size of your NEEDED INFO

"Ya Ya" wrote:

Hi,
I have a string with some fixed text and variable text.
For example: "this is a fixed text THE NEEDED INFO more more fixed text".
How do I get the the variable text (THE NEEDED INFO) from this string ?
A simple example will help.

Thanks.
ra***@hotmail.c om

[Ya Ya]

Thanks, but I am looking for example using REGEX.

ra***@hotmail.c om

"Alex Levi" <Al******@discu ssions.microsof t.com> wrote in message
news:44******** *************** ***********@mic rosoft.com...

Dim txt As String
txt = "this is a fixed text THE NEEDED INFO more more fixed text"
txt = Mid(txt, 23, txt.Length - 22)

23 <- starting index
txt.Length - 22 <- size of your NEEDED INFO

"Ya Ya" wrote:

Hi,
I have a string with some fixed text and variable text.
For example: "this is a fixed text THE NEEDED INFO more more fixed text".
How do I get the the variable text (THE NEEDED INFO) from this string ?
A simple example will help.

Thanks.
ra***@hotmail.c om

[chanmmn]

Dim text As String = "One car red car blue car"
Dim pat As String = "(\w+)\s+(c ar)"
' Compile the regular expression.
Dim r As Regex = new Regex(pat, RegexOptions.Ig noreCase)
' Match the regular expression pattern against a text string.
Dim m As Match = r.Match(text)
Dim matchcount as Integer = 0
While (m.Success)
matchCount += 1
Console.WriteLi ne("Match" & (matchCount))
Dim i As Integer
For i = 1 to 2
Dim g as Group = m.Groups(i)
Console.WriteLi ne("Group" & i & "='" & g.ToString() & "'")
Dim cc As CaptureCollecti on = g.Captures
Dim j As Integer
For j = 0 to cc.Count - 1
Dim c As Capture = cc(j)
Console.WriteLi ne("Capture" & j & "='" & c.ToString() _
& "', Position=" & c.Index)
Next j
Next i
m = m.NextMatch()
End While
chanmm
"Ya Ya" <ra***@hotmail. com> wrote in message
news:uU******** *****@TK2MSFTNG P12.phx.gbl...

Thanks, but I am looking for example using REGEX.

ra***@hotmail.c om

"Alex Levi" <Al******@discu ssions.microsof t.com> wrote in message
news:44******** *************** ***********@mic rosoft.com...

Dim txt As String
txt = "this is a fixed text THE NEEDED INFO more more fixed text"
txt = Mid(txt, 23, txt.Length - 22)

23 <- starting index
txt.Length - 22 <- size of your NEEDED INFO

"Ya Ya" wrote:

Hi,
I have a string with some fixed text and variable text.
For example: "this is a fixed text THE NEEDED INFO more more fixed
text".
How do I get the the variable text (THE NEEDED INFO) from this string ?
A simple example will help.

Thanks.
ra***@hotmail.c om

[David]

On 2004-10-23, Ya Ya <ra***@hotmail. com> wrote:

Hi,
I have a string with some fixed text and variable text.
For example: "this is a fixed text THE NEEDED INFO more more fixed text".
How do I get the the variable text (THE NEEDED INFO) from this string ?
A simple example will help.

Assuming you want to match by the surrounding text (as opposed to
matching all case, or whatever)...
Private Function DoMatch(ByVal input As String) As String
Dim pattern As String = "fixed text ([\w ]+) more more fixed text"

Dim match As System.Text.Reg ularExpressions .Match = _
System.Text.Reg ularExpressions .Regex.Match(in put, pattern)

If match.Length > 0 Then
Return match.Groups(1) .Value
Else
Return Nothing
End If

End Function