finding the list of the matched strings

[jm.suresh]

Hi, I have a list of strings. And I want to find the subset which
matches a particular regular expression.

import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = filter(lambda s: p.match(s), ll)

I suppose there should be simple function to do this in re module. Is
there any?

I searched google, but could not find one, may be for keywords were not
perfect.

Thanks.
Suresh

[Christian Joergensen]

"jm*******@no.spam.gmail.com" <jm*******@gmail.comwrites:

Hi, I have a list of strings. And I want to find the subset which
matches a particular regular expression.

import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = filter(lambda s: p.match(s), ll)

I suppose there should be simple function to do this in re module. Is
there any?

I searched google, but could not find one, may be for keywords were not
perfect.

I dont believe there exists such a function. I would have written
it using a list comprehension.

>>import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = [s for s in ll if p.match(s)]
newList

['s1', 's2']

--
Christian Joergensen | Linux, programming or web consultancy
http://www.razor.dk | Visit us at: http://www.gmta.info

[James Stroud]

jm*******@no.spam.gmail.com wrote:

Hi, I have a list of strings. And I want to find the subset which
matches a particular regular expression.

import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = filter(lambda s: p.match(s), ll)

I suppose there should be simple function to do this in re module. Is
there any?

I searched google, but could not find one, may be for keywords were not
perfect.

Thanks.
Suresh

I think I'm having some network problems. I'll try again. Also the
previous "attempt" had a typo (perhaps a freudian slip).

",".join(some_list).

By the way, don't name your own objects with the names of built-in
types, such as "list" or "str", etc.

[Gerard Flanagan]

jm*******@no.spam.gmail.com wrote:

Hi, I have a list of strings. And I want to find the subset which
matches a particular regular expression.

import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = filter(lambda s: p.match(s), ll)

I suppose there should be simple function to do this in re module. Is
there any?

#>>s = ('a', 'b', 's1', 's2', 'c')
#>>import re
#>>regexp = re.compile('^s.*')
#>>filter( regexp.match, s)
#('s1', 's2')
#>>>

Gerard

[Peter Otten]

jm*******@no.spam.gmail.com wrote:

Hi, I have a list of strings. And I want to find the subset which
matches a particular regular expression.

import re
ll = ('a', 'b', 's1', 's2', '3s')
p = re.compile('^s.*')
newList = filter(lambda s: p.match(s), ll)

or

newList = [s for s in ll if p.match(s)]

I suppose there should be simple function to do this in re module. Is
there any?

No.

Peter

[John Machin]

James Stroud wrote:
[snip]

I think I'm having some network problems. I'll try again. Also the
previous "attempt" had a typo (perhaps a freudian slip).

Also this time you replied to the wrong thread :-)

>
",".join(some_list).

By the way, don't name your own objects with the names of built-in
types, such as "list" or "str", etc.