Dear all,
this is really driving me nuts and any help would be extremely
appreciated.
I have a string that contains some numeric data. I want to isolate
these data using re.match, as follows.
bogus = "IFC(35m)"
data = re.match(r'(\d+ )',bogus)
print data.group(1)
I would expect to have "35" printed out to screen, but instead I get
an error that the regular expression did not match:
Traceback (most recent call last):
File "C:\Documen ts and Settings\Mattia \Desktop\Neeltj e\read.py",
line 20, in <module>
print data.group(1)
AttributeError: 'NoneType' object has no attribute 'group'
Note that the same holds if I look for "35" straight, instead of "\d
+". If instead I look for "IFC" it works fine. That is, apparently
re.match will match only up to the first non-alphanumeric character
and ignore anything after a "(", "_", "[" and god knows what else.
I am using Python 2.6 (r26:66721, latest stable version). Am I missing
something very big and very important?
8  5991 
On Nov 16, 10:33*am, The Web President <mattia.land... @gmail.com>
wrote:
Dear all,
this is really driving me nuts and any help would be extremely
appreciated.
I have a string that contains some numeric data. I want to isolate
these data using re.match, as follows.
bogus = "IFC(35m)"
data = re.match(r'(\d+ )',bogus)
print data.group(1)
I would expect to have "35" printed out to screen, but instead I get
an error that the regular expression did not match:
Traceback (most recent call last):
* File "C:\Documen ts and Settings\Mattia \Desktop\Neeltj e\read.py",
line 20, in <module>
* * print data.group(1)
AttributeError: 'NoneType' object has no attribute 'group'
Note that the same holds if I look for "35" straight, instead of "\d
+". If instead I look for "IFC" it works fine. That is, apparently
re.match will match only up to the first non-alphanumeric character
and ignore anything after a "(", "_", "[" and god knows what else.
I am using Python 2.6 (r26:66721, latest stable version). Am I missing
something very big and very important?
try re.search or re.findall
re.match is only at the beginning of a string
i almost never use it
>>re.search('(\ d+)', bogus).group()
'35'
>>re.search('(\ d+)', bogus).span()
(4, 6)
On Nov 16, 4:33*pm, The Web President <mattia.land... @gmail.com>
wrote:
Dear all,
this is really driving me nuts and any help would be extremely
appreciated.
I have a string that contains some numeric data. I want to isolate
these data using re.match, as follows.
bogus = "IFC(35m)"
data = re.match(r'(\d+ )',bogus)
print data.group(1)
I would expect to have "35" printed out to screen, but instead I get
an error that the regular expression did not match:
Traceback (most recent call last):
* File "C:\Documen ts and Settings\Mattia \Desktop\Neeltj e\read.py",
line 20, in <module>
* * print data.group(1)
AttributeError: 'NoneType' object has no attribute 'group'
Note that the same holds if I look for "35" straight, instead of "\d
+". If instead I look for "IFC" it works fine. That is, apparently
re.match will match only up to the first non-alphanumeric character
and ignore anything after a "(", "_", "[" and god knows what else.
I am using Python 2.6 (r26:66721, latest stable version). Am I missing
something very big and very important?
re.match() anchors the match at the start of the string. What you need
is re.search(). It's all in the documentation! :-)
En Sun, 16 Nov 2008 14:33:42 -0200, The Web President
<ma************ @gmail.comescri bió:
I have a string that contains some numeric data. I want to isolate
these data using re.match, as follows.
bogus = "IFC(35m)"
data = re.match(r'(\d+ )',bogus)
print data.group(1)
I would expect to have "35" printed out to screen, but instead I get
an error that the regular expression did not match:
http://docs.python.org/library/re.ht...g-vs-searching
--
Gabriel Genellina
The Web President wrote:
Dear all,
this is really driving me nuts and any help would be extremely
appreciated.
I have a string that contains some numeric data. I want to isolate
these data using re.match, as follows.
bogus = "IFC(35m)"
data = re.match(r'(\d+ )',bogus)
print data.group(1)
I would expect to have "35" printed out to screen, but instead I get
an error that the regular expression did not match:
Traceback (most recent call last):
File "C:\Documen ts and Settings\Mattia \Desktop\Neeltj e\read.py",
line 20, in <module>
print data.group(1)
AttributeError: 'NoneType' object has no attribute 'group'
Note that the same holds if I look for "35" straight, instead of "\d
+". If instead I look for "IFC" it works fine. That is, apparently
re.match will match only up to the first non-alphanumeric character
and ignore anything after a "(", "_", "[" and god knows what else.
I am using Python 2.6 (r26:66721, latest stable version). Am I missing
something very big and very important?
Yep - re.search. Match matches the whole string. You want searching.
Diez
On Nov 17, 4:44*am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
Match matches the whole string.
*ONLY* if the pattern ends with "$" or r"\Z"
John Machin schrieb:
On Nov 17, 4:44 am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
> Match matches the whole string.
*ONLY* if the pattern ends with "$" or r"\Z"
You think so?
import re
rex = re.compile("abc .*def")
if rex.match("abc0 123455678def"):
print "matched"
Diez
Diez B. Roggisch wrote:
John Machin schrieb:
>On Nov 17, 4:44 am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
>> Match matches the whole string.
*ONLY* if the pattern ends with "$" or r"\Z"
You think so?
import re
rex = re.compile("abc .*def")
if rex.match("abc0 123455678def"):
print "matched"
Your test is inconclusive: necessary, but not sufficient.
>>rex = re.compile("abc .*def")
if rex.match("abc0 123455678defPLU SEXTRASTUFF"):
.... print "Matched"
....
Matched
>>>
regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
On Nov 17, 10:19*am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
John Machin schrieb:
On Nov 17, 4:44 am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
*Match matches the whole string.
*ONLY* if the pattern ends with "$" or r"\Z"
You think so?
import re
rex = re.compile("abc .*def")
if rex.match("abc0 123455678def"):
* * *print "matched"
OK, I'll try again:
The following 3-tuples represent (pattern, string,
matched_portion _of_string):
('abc', 'abc', 'abc')
('abc', 'abcdef', 'abc')
('abc$', 'abc', 'abc')
('abc$', 'abcdef', '<no match>')
Saying "Match matches the whole string" is incorrect; see the second
case. If you want to ensure that the whole string matches the pattern,
the pattern needs to be terminated by "$" or "\Z". This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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