Hi all,
I am trying to redefine __setattr__.
The base class is in a library (actually, it is
win32com.client .DispatchBaseCl ass) and I do not want to touch it. My problem
is exemplified below. To my surprise, __setattr__ and __str__ behave
differently; I can redefine __str__ and the inherited __str__ is still the
redefined one. But redefining __setattr__ on the base class does not get
inherited. In Base.__dict__ the __setattr__ is the one I expected, but it is
not called from B.
What is the problem? Is __setattr__ cached somewhere [and not updated?]?
class Base:
def __setattr__(sel f, attr, value):
print 'Base __setattr__'
self.__dict__[attr] = value
def __str__(self):
return "Base"
class A(Base): pass
class B(Base): pass
def __setattr__(sel f, attr, value):
print 'alternative __setattr__'
self.__dict__[attr] = value
def __str__(self):
return "Alternativ e"
a = A()
b = B()
for i in (1, 2):
print
print 'run', i
print
print Base.__dict__
print A.__dict__
print B.__dict__
print
print 'a:', a
a.a1 = 1
print 'b:', b
b.b1 = 1
setattr(Base, '__setattr__', __setattr__)
setattr(A, '__setattr__', __setattr__)
setattr(Base, '__str__', __str__)
setattr(A, '__str__', __str__) 2 1424
Le Monday 15 September 2008 01:06:08 Jan Schilleman, vous avez écrit*:
Hi all,
I am trying to redefine __setattr__.
The base class is in a library (actually, it is
win32com.client .DispatchBaseCl ass) and I do not want to touch it. My
problem is exemplified below. To my surprise, __setattr__ and __str__
behave differently; I can redefine __str__ and the inherited __str__ is
still the redefined one. But redefining __setattr__ on the base class does
not get inherited. In Base.__dict__ the __setattr__ is the one I expected,
but it is not called from B.
What is the problem? Is __setattr__ cached somewhere [and not updated?]?
Yes, it doesn't work with classic classes, but do with new-style ones, I don't
know if this an accepted behavior or not.
Can't you use new-style classes ?
>>>[2]: sys.version
...[2]: '2.5.2 (r252:60911, May 28 2008, 19:19:25) \n[GCC 4.2.4 (Debian
4.2.4-1)]'
>>>[64]: class A :
def __setattr__(sel f, name, value) :
print "A", name
....:
....:
>>>[67]: class B(A) : pass
....:
>>>[68]: A().c, B().c = 1, 2
A c
A c
>>>[69]: A.__setattr__ = lambda s, n, v : sys.stdout.writ e("%s, %s, %s\n"%
(s, n, v))
>>>[70]: A().c, B().c = 1, 2
<__main__.A instance at 0x2b3b41546290> , c, 1
A c
>>>[71]: class A(object) :
def __setattr__(sel f, name, value) :
print "A", name
....:
....:
>>>[74]: class B(A) : pass
....:
>>>[75]: A().c, B().c = 1, 2
A c
A c
>>>[76]: A.__setattr__ = lambda s, n, v : sys.stdout.writ e("%s, %s, %s\n"%
(s, n, v))
>>>[77]:
>>>[78]: A().c, B().c = 1, 2
<__main__.A object at 0x2b3b45dfa350> , c, 1
<__main__.B object at 0x2b3b45dfa350> , c, 2
--
_____________
Maric Michaud
That still would require changing the source of the library ... And i'm not
sure if it would have side effects.
"Maric Michaud" <ma***@aristote .infoschreef in bericht
news:ma******** *************** *************** @python.org...
Le Monday 15 September 2008 01:06:08 Jan Schilleman, vous avez écrit :
Hi all,
I am trying to redefine __setattr__.
The base class is in a library (actually, it is
win32com.client .DispatchBaseCl ass) and I do not want to touch it. My
problem is exemplified below. To my surprise, __setattr__ and __str__
behave differently; I can redefine __str__ and the inherited __str__ is
still the redefined one. But redefining __setattr__ on the base class does
not get inherited. In Base.__dict__ the __setattr__ is the one I expected,
but it is not called from B.
What is the problem? Is __setattr__ cached somewhere [and not updated?]?
Yes, it doesn't work with classic classes, but do with new-style ones, I
don't
know if this an accepted behavior or not.
Can't you use new-style classes ?
>>>[2]: sys.version
....[2]: '2.5.2 (r252:60911, May 28 2008, 19:19:25) \n[GCC 4.2.4 (Debian
4.2.4-1)]'
>>>[64]: class A :
def __setattr__(sel f, name, value) :
print "A", name
....:
....:
>>>[67]: class B(A) : pass
....:
>>>[68]: A().c, B().c = 1, 2
A c
A c
>>>[69]: A.__setattr__ = lambda s, n, v : sys.stdout.writ e("%s, %s, %s\n" %
(s, n, v))
>>>[70]: A().c, B().c = 1, 2
<__main__.A instance at 0x2b3b41546290> , c, 1
A c
>>>[71]: class A(object) :
def __setattr__(sel f, name, value) :
print "A", name
....:
....:
>>>[74]: class B(A) : pass
....:
>>>[75]: A().c, B().c = 1, 2
A c
A c
>>>[76]: A.__setattr__ = lambda s, n, v : sys.stdout.writ e("%s, %s, %s\n" %
(s, n, v))
>>>[77]:
>>>[78]: A().c, B().c = 1, 2
<__main__.A object at 0x2b3b45dfa350> , c, 1
<__main__.B object at 0x2b3b45dfa350> , c, 2
--
_____________
Maric Michaud This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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