I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(")" , "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
15  1583 
gjhames:
What's the better way to do it?
Better is a relative term. If with better you mean "faster" (in some
circumstances), then the translate method is your friend, as you can
see its second argument are the chars to be removed. As first argument
you can use something like:
"".join(map(chr , xrange(256)))
If your strings are unicode you will need something different (a dict
with Null values for the key chars you want to remove).
Bye,
bearophile
I tend to use the re module like so :
import re
my_string = re.sub('[\-,./]','',my_string)
I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(")" , "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
Dnia Wed, 13 Aug 2008 09:39:53 -0700 (PDT), gjhames napisa³(a):
I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(")" , "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
The regular expression is probably the best way to do it,
but if you really want to use replace, you can also use
the replace method in loop:
>>somestr = "Qwe.Asd/Zxc()Poi-Lkj"
for i in '-./()':
.... somestr = somestr.replace (i, '')
....
>>somestr
'QweAsdZxcPoiLk j'
>>>
Next step would be to define your own replacing function:
def my_replace(myst r, mychars, myrepl):
"""Replace every character from 'mychars' string with 'myrepl' string
in 'mystr' string.
Example:
my_replace('Qwe .Asd/Zxc(', './(', 'XY') -'QweXYAsdXYZxcX Y'"""
for i in mychars:
mystr = mystr.replace(i , myrepl)
return mystr
--
Regards,
Wojtek Walczak, http://www.stud.umk.pl/~wojtekwa/
Wojtek Walczak wrote:
>I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(") ", "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
The regular expression is probably the best way to do it,
but if you really want to use replace, you can also use
the replace method in loop:
suggested exercise: benchmark re.sub with literal replacement, re.sub
with callback (lambda m: ""), repeated replace, and repeated use of the form
if ch in my_string:
my_string = my_string.repla ce(ch, "")
on representative data.
</F>
Fredrik Lundh:
suggested exercise: benchmark re.sub with literal replacement, re.sub
with callback (lambda m: ""), repeated replace, and repeated use of the form
....
on representative data.
Please, add the translate() solution too I have suggested :-)
Bye,
bearophile
On Wed, 2008-08-13 at 09:39 -0700, gjhames wrote:
I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(")" , "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
--
http://mail.python.org/mailman/listinfo/python-list
The maketrans interface is a bit clunky, but this is what
string.translat e is best at:
>>import string
>>'-./other'.translat e( string.maketran s( '', '' ), '-./' )
'other'
It'd be interesting to see where it falls in the benchmarks, though.
It's worth noting that the interface for translate is quite different
for unicode strings.
--
John Krukoff <jk******@ltgc. com>
Land Title Guarantee Company
Dnia Wed, 13 Aug 2008 23:31:42 +0200, Fredrik Lundh napisa³(a):
>>I wish to replace several characters in my string to only one.
Example, "-", "." and "/" to nothing ""
I did like that:
my_string = my_string.repla ce("-", "").replace("." , "").replace ("/",
"").replace(" )", "").replace("(" , "")
But I think it's a ugly way.
What's the better way to do it?
The regular expression is probably the best way to do it,
but if you really want to use replace, you can also use
the replace method in loop:
suggested exercise: benchmark re.sub with literal replacement, re.sub
with callback (lambda m: ""), repeated replace, and repeated use of the form
if ch in my_string:
my_string = my_string.repla ce(ch, "")
on representative data.
I don't have to, I can anticipate the results. I mentioned above
that using re is the best approach, but if one really wants to use
replace() multiple times (which will be slow, of course), it can
be done a bit cleaner than with str.replace().r eplace().replac e()...
--
Regards,
Wojtek Walczak, http://www.stud.umk.pl/~wojtekwa/
Wojtek Walczak wrote:
>suggested exercise: benchmark re.sub with literal replacement, re.sub
with callback (lambda m: ""), repeated replace, and repeated use of the form
if ch in my_string:
my_string = my_string.repla ce(ch, "")
on representative data.
I don't have to, I can anticipate the results.
Chances are that you're wrong.
</F>
Dnia Thu, 14 Aug 2008 00:31:00 +0200, Fredrik Lundh napisa³(a):
>> if ch in my_string:
my_string = my_string.repla ce(ch, "")
on representative data.
I don't have to, I can anticipate the results.
Chances are that you're wrong.
At the moment my average is about 0.75 of mistake per
post on comp.lang.pytho n (please, bare with me ;-)).
I strongly believe that the statement I made above won't
make this number rise.
:)
--
Regards,
Wojtek Walczak, http://www.stud.umk.pl/~wojtekwa/ This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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