is the a problem with this code

[thatos]

I was requested to make a code for the following question
write a program that will compute the frequency that the 13th of each month lands on sunday,monday,t uesday,wednesda y,thursday,frid ay and saturday over a given period of N years.
input format: must read a single integer from file friday.in
output format: must write the following in file friday.out ; seven space separated integers on one line.These intergers represent the number of times the 13th falls on Saturday.Sunday ,Monday,.....,F riday.
here is my python code:

def friday():
    f = open("friday.in",'r')
    out = open("friday.out",'w')
    s = f.readline()
                ss = int(s[0])
    day = 13
    year = 1900
    thirteenthcounter = {"monday":0,"tuesday":0,"wednesday":0,"thursday":0,"friday":0,"saturday":0,"sunday":0}
    nummonths = {1:"january",2:"february",3:"march",4:"april",5:"may",6:"june",7:"july",8:"august",9:"september",10:"october",11:"november",12:"december"}
    while (year < year + int(s[0])):
        if (year % 4 == 0) or (year%100 == 0 and year%400 == 0):
            months = {"january":31,"february":29,"march":31,"april":30,"may":31,"june":30,"july":31,"august":31,"september":30,"october":31,"november":30,"december":31}
        else:
            months = {"january":31,"february":28,"march":31,"april":30,"may":31,"june":30,"july":31,"august":31,"september":30,"october":31,"november":30,"december":31}
        month = 1
        while month <= 12:
            if day % 7 == 1:
                thirteenthcounter["monday"] += 1
            elif day % 7 == 2:
                thirteenthcounter["tuesday"] += 1
            elif day % 7 == 3:
                thirteenthcounter["wednesday"] += 1
            elif day % 7 == 4:
                thirteenthcounter["thursday"] += 1
            elif day % 7 == 5:
                thirteenthcounter["friday"] += 1
            elif day % 7 == 6:
                thirteenthcounter["saturday"] += 1
            else:
                thirteenthcounter["sunday"] += 1
            day += months[nummonths[month]]
            month += 1
        year += 1
    out.write[thirteenthcounter["saturday"]+" "+thirteenthcounter["sunday"]+ " " + thirteenthcounter["monday"]+ " "+thirteenthcounter["tuesday"]+" "+thirteenthcounter["wednesday"]+" "+thirteenthcounter["thursday"]+" "+thirteenthcounter["friday"]+"\n"]
    out.close()
 

If I made some mistakes please tell me where they are and if the is not problem with the code please tell me what is the result when you have 20 years or try to make it shorter.

[bvdet]

I was requested to make a code for the following question
write a program that will compute the frequency that the 13th of each month lands on sunday,monday,t uesday,wednesda y,thursday,frid ay and saturday over a given period of N years.
input format: must read a single integer from file friday.in
output format: must write the following in file friday.out ; seven space separated integers on one line.These intergers represent the number of times the 13th falls on Saturday.Sunday ,Monday,.....,F riday.
here is my python code:

def friday():
    f = open("friday.in",'r')
    out = open("friday.out",'w')
    s = f.readline()
                ss = int(s[0])
    day = 13
    year = 1900
    thirteenthcounter = {"monday":0,"tuesday":0,"wednesday":0,"thursday":0,"friday":0,"saturday":0,"sunday":0}
    nummonths = {1:"january",2:"february",3:"march",4:"april",5:"may",6:"june",7:"july",8:"august",9:"september",10:"october",11:"november",12:"december"}
    while (year < year + int(s[0])):
        if (year % 4 == 0) or (year%100 == 0 and year%400 == 0):
            months = {"january":31,"february":29,"march":31,"april":30,"may":31,"june":30,"july":31,"august":31,"september":30,"october":31,"november":30,"december":31}
        else:
            months = {"january":31,"february":28,"march":31,"april":30,"may":31,"june":30,"july":31,"august":31,"september":30,"october":31,"november":30,"december":31}
        month = 1
        while month <= 12:
            if day % 7 == 1:
                thirteenthcounter["monday"] += 1
            elif day % 7 == 2:
                thirteenthcounter["tuesday"] += 1
            elif day % 7 == 3:
                thirteenthcounter["wednesday"] += 1
            elif day % 7 == 4:
                thirteenthcounter["thursday"] += 1
            elif day % 7 == 5:
                thirteenthcounter["friday"] += 1
            elif day % 7 == 6:
                thirteenthcounter["saturday"] += 1
            else:
                thirteenthcounter["sunday"] += 1
            day += months[nummonths[month]]
            month += 1
        year += 1
    out.write[thirteenthcounter["saturday"]+" "+thirteenthcounter["sunday"]+ " " + thirteenthcounter["monday"]+ " "+thirteenthcounter["tuesday"]+" "+thirteenthcounter["wednesday"]+" "+thirteenthcounter["thursday"]+" "+thirteenthcounter["friday"]+"\n"]
    out.close()
 

If I made some mistakes please tell me where they are and if the is not problem with the code please tell me what is the result when you have 20 years or try to make it shorter.

Your logic looks sound. Here's a way to determine the frequency using the datetime module, dictionary method setdefault(), and a list comprehension:

def day_freq(day_of_month, start_yr, end_yr):
    weekdays = ['Monday', 'Tuesday', 'Wednesday', \
                'Thursday','Friday', 'Saturday', 'Sunday']
    weekdayDict = dict(zip(range(0,7), weekdays))
    dateList = [weekdayDict[datetime.date(y,m,day_of_month).weekday()] \
                for m in range(1,13) for y in range(start_yr,end_yr)]    
    dayDict = {}
    for day in dateList:
        dayDict[day] = dayDict.setdefault(day, 0)+1    
    for day in weekdays:
        print '%s occurred %d time%s.' % \
              (day, dayDict.get(day, 0), ['', 's'][dayDict[day]>1 or 0])

Example:

>>> day_freq(1, 1951, 1952)
Monday occurred 2 times.
Tuesday occurred 1 time.
Wednesday occurred 1 time.
Thursday occurred 3 times.
Friday occurred 1 time.
Saturday occurred 2 times.
Sunday occurred 2 times.
>>>