Please see the followed example:
class A:
def __init__(self):
pass
class X:
def __init__(self):
n = 200
if True:
j = 200
m = j
k = A()
print m, j
a = X()
# ?? what about the m, n and j? is it still alive?
del a
--------------------------
In C/C++, the life time of m,n and j was the nearest block. but
obviously, python doen't have this syntax, but I would like to know
that whether the life time of m, n, j is base on function range or
the object range.
We can not access the m, n, and j from the outside of class X. Now I'm
writing a program base on the wxpython. In the __init__ function of
wx.Panel, I use normal varable(just like the m,n and j) created some
widgets. It could be show in the window. Does it indicated the life
time of varable m,n,j is base on the object range?
Sorry for my poor english!
It seems 2 1269
人言落日是 天涯,望极 天涯不见家 wrote:
Please see the followed example:
class A:
def __init__(self):
pass
class X:
def __init__(self):
n = 200
if True:
j = 200
m = j
k = A()
print m, j
a = X()
# ?? what about the m, n and j? is it still alive?
del a
--------------------------
In C/C++, the life time of m,n and j was the nearest block. but
obviously, python doen't have this syntax, but I would like to know
that whether the life time of m, n, j is base on function range or
the object range.
We can not access the m, n, and j from the outside of class X. Now I'm
writing a program base on the wxpython. In the __init__ function of
wx.Panel, I use normal varable(just like the m,n and j) created some
widgets. It could be show in the window. Does it indicated the life
time of varable m,n,j is base on the object range?
Python has no variables. It has objects, which can be bound to names. Each
binding to a name will increase a reference counter. Each unbinding will
decrease it. so
a = SomeObject()
b = a
del a
will result in the SomeObject-instance still be alive. But when you add
del b
it will be garbage collected.
Now in your example A() bound to k will not survive the exit of the method,
as that means that k goes out of scope, and the object is bound to - the
A-instance - gets its reference-counter decreased, resulting in it being
freed.
The wxwidgets example though is a different thing. If the panel stores a
reference to the object, e.g. via a list (being part of a list or dict also
increases the reference count), it will be kept around.
Diez
On Apr 30, 5:20*pm, "Diez B. Roggisch" <d...@nospam.we b.dewrote:
人言落日是 天涯,望极 天涯不见家 wrote:
Please see the followed example:
class A:
* * def __init__(self):
* * * * pass
class X:
* * def __init__(self):
* * * * n = 200
* * * * if True:
* * * * * * j = 200
* * * * m = j
* * * * k = A()
* * * * print m, j
a = X()
# ?? what about the m, n and j? is it still alive?
del a
--------------------------
In C/C++, the life time of m,n and j was the nearest block. *but
obviously, python doen't have this syntax, but I would like to know
that whether the life time of *m, n, j *is base on function range or
the object range.
We can not access the m, n, and j from the outside of class X. Now I'm
writing a program base on the wxpython. In the __init__ function of
wx.Panel, I use normal varable(just like the m,n and j) created some
widgets. It could be show in the window. *Does it indicated the life
time of varable m,n,j is base on the object range?
Python has no variables. It has objects, which can be bound to names. Each
binding to a name will increase a reference counter. Each unbinding will
decrease it. so
a = SomeObject()
b = a
del a
will result in the SomeObject-instance still be alive. But when you add
del b
it will be garbage collected.
Now in your example A() bound to k will not survive the exit of the method,
as that means that k goes out of scope, and the object is bound to - the
A-instance - gets its reference-counter decreased, resulting in it being
freed.
The wxwidgets example though is a different thing. If the panel stores a
reference to the object, e.g. via a list (being part of a list or dict also
increases the reference count), it will be kept around.
Diez- Hide quoted text -
- Show quoted text -
Yes, I see. Many thanks for you ! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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