search substring in list of strings

[eso40043]

Hello.

Is there an easy one-line way to see if a list of strings contains at least one occurance of a substring? E.g.

string_list=["PG2213-006B","PG0231+0 51E","PG2213-006A"]

substring_list=["PG2213-006","PG0231"]


I really don't want to loop, as I loop too many times in my code already.

Here's the way it is now:

images is a list of image names

refdict contains full names as keys

hdrs contains some of those keys but truncated

for image in images:
 for x in refdict.keys(): if x.find(hdrs[image]['some keyword']) != -1: print "Already have that key, skipping image."

but this way I have to either continue with the checking of the substring even after I've found it once or insert a break statement which means another if-control statement which means more incomprehensibl e code.

I tried with something like

if x.find(hdrs[image]['some keyword']) !=-1 for x in refdict.keys():
 

but that naturally didn't want to work for me. Is there a way of using has_key but only make it find a substring of the key instead of the whole key?


any help will be greatly appreciated!

[bvdet]

Hello.

Is there an easy one-line way to see if a list of strings contains at least one occurance of a substring? E.g.

string_list=["PG2213-006B","PG0231+0 51E","PG2213-006A"]

substring_list=["PG2213-006","PG0231"]


I really don't want to loop, as I loop too many times in my code already.

Here's the way it is now:

images is a list of image names

refdict contains full names as keys

hdrs contains some of those keys but truncated

for image in images:
 for x in refdict.keys(): if x.find(hdrs[image]['some keyword']) != -1: print "Already have that key, skipping image."

but this way I have to either continue with the checking of the substring even after I've found it once or insert a break statement which means another if-control statement which means more incomprehensibl e code.

I tried with something like

if x.find(hdrs[image]['some keyword']) !=-1 for x in refdict.keys():
 

but that naturally didn't want to work for me. Is there a way of using has_key but only make it find a substring of the key instead of the whole key?


any help will be greatly appreciated!

Maybe you can use this:

import re
 
string_list=["PG2213-006B","PG0231+051E","PG2213-006A"]
 
substring_list=["PG2213-005","PG0231","D0000","PG2213-006"]
 
patt = r'%s' % '|'.join(substring_list)
print [re.match(patt, i) for i in string_list]
 
if None not in [re.match(patt, i) for i in string_list]:
    print 'Perform some action'
else:
    print 'No match'
 
'''
>>> [<_sre.SRE_Match object at 0x00E1A4B8>, <_sre.SRE_Match object at 0x00E1A4F0>, <_sre.SRE_Match object at 0x00E1A528>]
Perform some action
>>> 
'''

[ghostdog74]

Hello.

Is there an easy one-line way to see if a list of strings contains at least one occurance of a substring? E.g.

string_list=["PG2213-006B","PG0231+0 51E","PG2213-006A"]

substring_list=["PG2213-006","PG0231"]

using simple string methods

>>> string_list=' '.join(["PG2213-006B","PG0231+051E","PG2213-006A"])
>>> substring_list=["PG2213-006","PG0231"]
>>> for i in substring_list:
...  if i in string_list:
...   print "substring ", i , "found"
...
substring  PG2213-006 found
substring  PG0231 found
>>>                                  
 

[eso40043]

Thanks a bunch, guys!