Hi,
I am using Python 2.4. I read the PEP 308 at: http://www.python.org/dev/peps/pep-0308/
I tried the statement:
a= "Yes" if 1==1 else "No"
but the interpreter doesn't accept it.
Do we have the conditional expressions in Python 2.4?
Thank you,
Alan 5  1699 
A.M wrote: Do we have the conditional expressions in Python 2.4?
No.
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
A.M wrote: Hi,
I am using Python 2.4. I read the PEP 308 at:
http://www.python.org/dev/peps/pep-0308/
I tried the statement:
a= "Yes" if 1==1 else "No"
but the interpreter doesn't accept it.
Do we have the conditional expressions in Python 2.4?
No, AFAIK they'll be in for 2.5
In the meanwhile, there are (sometime trickyà ways to get the same result:
a = 1 == 1 and "Yes" or "No"
a = ("No", "Yes")[1 == 1]
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in 'o****@xiludom. gro'.split('@')])" a = 1 == 1 and "Yes" or "No"
a = ("No", "Yes")[1 == 1]
Smart! Thanks alot.
A.M wrote: Do we have the conditional expressions in Python 2.4?
bruno at modulix wrote: No, AFAIK they'll be in for 2.5
Yep:
Python 2.5a2 (trunk:46491M, May 27 2006, 14:43:55) [MSC v.1310 32 bit
(Intel)] on win32 "Yes" if 1 == 1 else "No"
'Yes'
In the meanwhile, there are (sometime trickyà ways to get the same result:
a = 1 == 1 and "Yes" or "No"
a = ("No", "Yes")[1 == 1]
And just to give some examples where the conditional expression will
show a difference::
True and 0 or []
[] 0 if True else []
0
def f():
.... print "don't evaluate me"
.... return 'f'
.... def g():
.... return 'g'
.... (f(), g())[True]
don't evaluate me
'g' g() if True else f()
'g'
STeVe
Steven Bethard a écrit : A.M wrote: > Do we have the conditional expressions in Python 2.4?
bruno at modulix wrote:
(snip) In the meanwhile, there are (sometime trickyà ways to get the same
result:
a = 1 == 1 and "Yes" or "No"
a = ("No", "Yes")[1 == 1]
And just to give some examples where the conditional expression will
show a difference::
>>> True and 0 or [] []
Yes, this is one of the tricky part !-)
<op>
Always make sure the second term doesn't eval to False.
</op>
>>> def f(): ... print "don't evaluate me"
... return 'f'
... >>> def g(): ... return 'g'
... >>> (f(), g())[True]
Why on earth are you calling the callables *before* testing ?
Should be:
(f, g)[True]()
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