Is there an equivalent to the unix 'file' command?
[mark tmp]$ file min.txt
min.txt: ASCII text
[mark tmp]$ file trunk
trunk: directory
[mark tmp]$ file compliance.tgz
compliance.tgz: gzip compressed data, from Unix
What I really want to do is determine if a file is 1) a directory, 2) a
text file 3) a binary file.
Is there a way to do this?
Mark 3 2434
Mark Gibson wrote: Is there an equivalent to the unix 'file' command?
[mark tmp]$ file min.txt min.txt: ASCII text [mark tmp]$ file trunk trunk: directory [mark tmp]$ file compliance.tgz compliance.tgz: gzip compressed data, from Unix
What I really want to do is determine if a file is 1) a directory, 2) a text file 3) a binary file.
Is there a way to do this?
Mark
import os
def test_file(filen ame, maxread=1024):
if os.path.isdir(f ilename):
return 'directory'
afile = open(filename) # open as text
for achar in afile.read(maxr ead):
if ord(achar) > 127:
return 'binary'
return 'text'
James
--
James Stroud
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095 http://www.jamesstroud.com/
import os def test_file(filen ame, maxread=1024): if os.path.isdir(f ilename): return 'directory' afile = open(filename) # open as text for achar in afile.read(maxr ead): if ord(achar) > 127: return 'binary' return 'text'
Pefect, thanks!
On Sun, 26 Mar 2006 19:52:32 -0700, Mark Gibson wrote:
import os def test_file(filen ame, maxread=1024): if os.path.isdir(f ilename): return 'directory' afile = open(filename) # open as text for achar in afile.read(maxr ead): if ord(achar) > 127: return 'binary' return 'text'
Pefect, thanks!
Not only is it not perfect, as given it isn't even correct. open("lots_of_n ulls.bin", "w").write( "\0" * 1024) test_file("lots _of_nulls.bin")
'text'
However, with a more careful algorithm for deciding what's text and what's
not, the general approach is fine.
--
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