simple string search and replace

[Kun]

hey guys, here's my code,

senders = [('460 (BODY[HEADER.FIELDS (FROM)] {46}', 'From: Friend
<an**@anon.whar ton.com>\r\n\r\ n'), ')', ('462 (BODY[HEADER.FIELDS
(FROM)] {37}', 'From: Kun <ne*******@gmai l.com>\r\n\r\n' ), ')']
print senders
parsed_senders = []
sender = ""
for item in senders:
if isinstance(item ,tuple):
item= ''.join(item)
if item==')':
parsed_senders. append(sender[sender.find('<' )+1:].strip())
sender = ""
else:
sender+=item
print parsed_senders


wondering if anyone knows how i can remove the '>'s from the list, which
outputs to something like ['an**@anon.whar ton.com>', 'ne*******@gmai l.com>']

[bearophileHUGS]

Generally, to remove a substring (like ">") from a string you can use
the replace method (that returns a new string):

s = "...anon.wharto n.com>..."
s.replace(">", "")

'...anon.wharto n.com...'

You can use it with something like:
print [s.replace(">", "") for s in parsed_senders]

or you can put the replace() somewhere in the main loop.

Probably to solve your problem there are other solutions, like using a
RE to find email addresses inside the string...

Bye,
bearophile

[Steve Holden]

Kun wrote:

hey guys, here's my code,

senders = [('460 (BODY[HEADER.FIELDS (FROM)] {46}', 'From: Friend
<an**@anon.whar ton.com>\r\n\r\ n'), ')', ('462 (BODY[HEADER.FIELDS
(FROM)] {37}', 'From: Kun <ne*******@gmai l.com>\r\n\r\n' ), ')']
print senders
parsed_senders = []
sender = ""
for item in senders:
if isinstance(item ,tuple):
item= ''.join(item)
if item==')':
parsed_senders. append(sender[sender.find('<' )+1:].strip())
sender = ""
else:
sender+=item
print parsed_senders


wondering if anyone knows how i can remove the '>'s from the list, which
outputs to something like ['an**@anon.whar ton.com>', 'ne*******@gmai l.com>']

Where you append to parsed_senders, replace

sender[sender.find('<' )+1:]

with

sender[sender.find('<' )+1:-1]

and that will use a string one shorter, omitting the ">" character.

regards
Steve
--
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