How to find out the next Friday using RelativeDateTim e

[vj]

I'm doing:

a = now()
delta = ReltaiveDateTim e(days=+6, weekday(mx.Date Time.Friday, 0))
Next Friday: a+delta

a: march 23
a+delta: Gives me March 31st and not March 24th

Any ideas?

[vj]

I figured out how to do it. This does not work:

delta = ReltaiveDateTim e(days=0, weekday(mx.Date Time.Friday, 0))

But this works:

delta = ReltaiveDateTim e(days=+0, weekday(mx.Date Time.Friday, 0))

[John Machin]

On 24/03/2006 5:18 AM, Dennis Lee Bieber wrote:

On 23 Mar 2006 09:37:13 -0800, "vj" <vi******@gmail .com> declaimed the
following in comp.lang.pytho n:

I'm doing:

a = now()
delta = ReltaiveDateTim e(days=+6, weekday(mx.Date Time.Friday, 0))
Next Friday: a+delta

a: march 23
a+delta: Gives me March 31st and not March 24th

Any ideas?

Off-hand? (Since I don't think I have that function)...

Don't add the 6... It would appear that you are jumping over the
24th, and then picking up the first Friday that follows the result of
jumping.

Good call, Dennis.

vj: It would help for future questions if you were to copy and paste
code that you had actually run, rather than typing it from memory. There
are TWO typos in what your wrote. It would also help if you showed
exactly what import statement(s) were used, as in the following (where I
have substituted Saturday for Friday, in the interests of reproducing
your (volatile) test case).

from mx.DateTime import *
a = now()
a <DateTime object for '2006-03-24 06:13:46.89' at b00760> delta=RelativeD ateTime(days=6, weekday=(Saturd ay, 0))
a + delta <DateTime object for '2006-04-01 06:13:46.89' at ae6620> delta=RelativeD ateTime(weekday =(Saturday, 0))
a + delta <DateTime object for '2006-03-25 06:13:46.89' at b00aa0>

Hope this helps,
John

[vj]

Thanks for pointing out that the days=+0 is not necessary. Your other
points are well noted.

Thanks

VJ

[John Machin]

On 24/03/2006 6:30 AM, vj wrote:

I figured out how to do it. This does not work:

delta = ReltaiveDateTim e(days=0, weekday(mx.Date Time.Friday, 0))

But this works:

delta = ReltaiveDateTim e(days=+0, weekday(mx.Date Time.Friday, 0))

vj, NEITHER of those work, because you still have the two typos.
Secondly, there is absolutely no difference in Python between 0 and +0.
PLEASE post actual code (plus the results of running it), like this
(which continues from my previous posting):

delta2=Relative DateTime(days=0 , weekday=(Saturd ay, 0))
delta3=Relative DateTime(days=+ 0, weekday=(Saturd ay, 0))
delta2 <RelativeDateTi me instance for 'YYYY-MM-DD Sat:0 HH:MM:SS' at 0xae5f08> delta3 <RelativeDateTi me instance for 'YYYY-MM-DD Sat:0 HH:MM:SS' at 0xb01468> a+delta2 == a+delta3 True a+delta == a+delta2 == a+delta3 True

Cheers,
John

[fumanchu]

> a = now()

delta = ReltaiveDateTim e(days=+6, weekday(mx.Date Time.Friday, 0))
Next Friday: a+delta
a: march 23
a+delta: Gives me March 31st and not March 24th
Any ideas?

Just an off-beat idea: use Python's datetime instead of mx.DateTime,
and my recur module:
http://projects.amor.org/misc/wiki/Recur

import datetime, recur
recur.Recurrenc e(datetime.date .today(), "Friday").next( )

datetime.date(2 006, 3, 24)
Robert Brewer
System Architect
Amor Ministries
fu******@amor.o rg