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On Sun, Jun 12, 2005 at 04:55:38PM -0700, Xah Lee wrote: if i have mytext.replace( a,b) how to find out many many occurances has been replaced?
The count isn't returned by the replace method. You'll have to count
and then replace.
def count_replace(a , b, c):
count = a.count(b)
return count, s.replace(b, c) count_replace(" a car and a carriage", "car", "bat")
(2, 'a bat and a batriage')
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.2.6 (GNU/Linux)
iD8DBQFCrOQSJd0 1MZaTXX0RAm27AJ 47sF1yYVKYIboeS sIcAVQZuhaGPgCf RqRH
mdJtjbwypq/h7XcmVpZOfhs=
=9m3p
-----END PGP SIGNATURE-----
"Jeff Epler" wrote: On Sun, Jun 12, 2005 at 04:55:38PM -0700, Xah Lee wrote: if i have mytext.replace( a,b) how to find out many many occurances has been replaced?
The count isn't returned by the replace method. You'll have to count and then replace.
def count_replace(a , b, c): count = a.count(b) return count, s.replace(b, c)
count_replace(" a car and a carriage", "car", "bat")
(2, 'a bat and a batriage')
I thought naively that scanning a long string twice would be almost
twice as slow compared to when counting was done along with replacing.
Although it can done with a single scan, it is almost 9-10 times
slower, mainly because of the function call overhead; the code is also
longer:
import re
def count_replace_s low(aString, old, new):
count = [0]
def counter(match):
count[0] += 1
return new
replaced = re.sub(old,coun ter,aString)
return count[0], replaced
A good example of trying to be smart and failing :)
George
Xah Lee <xa*@xahlee.org > wrote: if i have mytext.replace( a,b) how to find out many many occurances has been replaced?
If 'a' and 'b' are different length,
- Count the string length, before and after. The difference should
be multiple of difference between length of 'a' and 'b'.
If they are same length,
- Split 'mytext', and count items.
--
William Park <op**********@y ahoo.ca>, Toronto, Canada
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Hi All,
Thanks a lot for all your replies.
My requirement is as follows:
I need to read a text file, eliminate certain special characters(like !
, - = + ), and then convert it to lower case and then remove certain
stopwords(like and, a, an, by, the etc) which is there in another txt
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Then, i need to run it thru a stemmer(a program which converts words
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I am wanting to find any instance in a string where more then on occurance of a value occurs and replace it with a single occurance of the value. Specifically I want to search a text field and find any time where more then a single ' (tic) occurs in succession, and replace it with a single ' (tic).
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Dear friends
I have a large string with the character "*" spread randomly in the string.
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Regards Able
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Hi,
My VB is very rusty I'm afraid! What would be the most efficient way to
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à è ì ò ù À È Ì Ò Ù
á é í ó ú ý Á É Í Ó Ú Ý
â ê î ô û Â Ê Î Ô Û
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I need to replace all occurances of a certain character located between
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Do you have any answer to it? thx.
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