re.match versus re.findall

[JerryB]

Hi,
I have a string like this:

invalidStr = "192.168.*. 1"

I want to be sure I don't get a * followed by a number, i.e. I want
invalidStr to be invalid. So I do:

numberAfterStar = re.compile(r'\* .*\d')

Now, here's the fun:

If I run:
if numberAfterStar .findall(invali dStr):
print "Found it with findall!"

it prints, if I run:

if numberAfterStar .match(invalidS tr):
print "Found it with match!"

it doesn't.
Why does findall finds a match it but match doesn't?

Thanks!
Jerry

[Peter Hansen]

JerryB wrote:

I have a string like this:

invalidStr = "192.168.*. 1"

I want to be sure I don't get a * followed by a number, i.e. I want
invalidStr to be invalid. So I do:

numberAfterStar = re.compile(r'\* .*\d')

Now, here's the fun:

If I run:
if numberAfterStar .findall(invali dStr):
print "Found it with findall!"

it prints, if I run:

if numberAfterStar .match(invalidS tr):
print "Found it with match!"

it doesn't.
Why does findall finds a match it but match doesn't?

This might help:

numberAfterStar .findall(invali dStr) ['*.1'] numberAfterStar .match(invalidS tr)
numberAfterStar .search(invalid Str)

<_sre.SRE_Mat ch object at 0x00AF3DB0>

Check the docs on match, specifically where it talks about when you
should use search() instead... (http://docs.python.org/lib/re-objects.html)

(By the way, thank you for the excellently crafted post. I wish
everyone who asked questions here took the time to prepare as thoroughly
and include the actual failing code, etc...)

-Peter