Hello,
I want to open the file 'configuration. smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.s mo', 'r')
What is the os-independent version of this line?
(I have read the manual of the module os, but I didn't see how to do
it.)
Jörg Schuster
5  1408 
I believe you want:
import os
f = open(os.path.jo in(dir, 'configuration. smo'), 'r')
....
Joerg Schuster wrote: Hello,
I want to open the file 'configuration. smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.s mo', 'r')
What is the os-independent version of this line?
(I have read the manual of the module os, but I didn't see how to do
it.)
Jörg Schuster
--
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Andrew Bushnell
Lead Development Engineer
Fluent Inc.
10 Cavendish Court
Centerra Resource Park
Lebanon, NH 03766 aw*@fluent.com
Phone: 603-643-2600, ext. 757
Fax: 603-643-1721 www.fluent.com
*************** *************** ******
Hi,
it`s
import os
f = open( os.path.join( dir , 'configuration. smo' ), 'r' )
HTH,
Gerald
Joerg Schuster schrieb: Hello,
I want to open the file 'configuration. smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.s mo', 'r')
What is the os-independent version of this line?
(I have read the manual of the module os, but I didn't see how to do
it.)
Jörg Schuster
--
GPG-Key: http://keyserver.veridis.com:11371/search?q=0xA140D634
Thanks, Andrew and Gerald.
Jörg
Gerald Klix schrieb: Hi,
it`s
import os
f = open( os.path.join( dir , 'configuration. smo' ), 'r' )
*nix-heads everywhere?
For a text file, I would prefer:
f = open( os.path.join( dir , 'configuration. smo' ), 'U' )
and for a binary file:
f = open( os.path.join( dir , 'configuration. smo' ), 'rb' )
That way it also works on Windows.
Thomas
Joerg Schuster schrieb:
Hello,
I want to open the file 'configuration. smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.s mo', 'r')
What is the os-independent version of this line?
(I have read the manual of the module os, but I didn't see how to do
it.)
Jörg Schuster
Joerg Schuster schrieb: Hello,
I want to open the file 'configuration. smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.s mo', 'r')
What is the os-independent version of this line?
Did You check this out on Windows? My experience with *nix paths is
that they work. open("C:/bla.txt")
<open file 'C:/bla.txt', mode 'r' at 0x026B4A20>
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