count files in a directory

[rbt]

I assume that there's a better way than this to count the files in a
directory recursively. Is there???

def count_em(valid_ path):
x = 0
for root, dirs, files in os.walk(valid_p ath):
for f in files:
x = x+1
print "There are", x, "files in this directory."
return x

rbt

[Steven Bethard]

rbt wrote:

Heiko Wundram wrote:

> import os
> path = "/home/heiko"
> file_count = sum((len(f) for _, _, f in os.walk(path)))
> file_count

Thanks! that works great... is there any significance to the underscores
that you used? I've always used root, dirs, files when using os.walk()
do the underscores make it faster... or more efficient?

No, they don't make any semantic difference; they work just like any
other identifier. It's just that, by convention, single underscores
indicate that we don't care what values these names are bound to. So in
the example above, Heiko indicates that we don't care about what you
would normally call 'root' and 'dirs'.

HTH,

STeVe