how to improve this simple block of code

[py]

Say I have...
x = "132.00"

but I'd like to display it to be "132" ...dropping the trailing
zeros...I currently try this

if x.endswith("0") :
x = x[:len(x)-1]
if x.endswith("0") :
x = x[:len(x)-1]
if x.endswith(".") :
x = x[:len(x)-1]

I do it like this because if
x = "132.15" ...i dont want to modify it. But if
x = "132.60" ...I want it to become "132.6"

is there a better way to do this? It seems a bit ugly to me.

T.I.A
(thanks in advance)

[Juho Schultz]

py wrote:

Say I have...
x = "132.00"

but I'd like to display it to be "132" ...dropping the trailing
zeros...I currently try this

if x.endswith("0") :
x = x[:len(x)-1]
if x.endswith("0") :
x = x[:len(x)-1]
if x.endswith(".") :
x = x[:len(x)-1]

I do it like this because if
x = "132.15" ...i dont want to modify it. But if
x = "132.60" ...I want it to become "132.6"

is there a better way to do this? It seems a bit ugly to me.

T.I.A
(thanks in advance)

x = x.rstrip('0') # removes trailing zeros
x = x.rstrip('.') # removes trailing dot(s)

[hanz]

Or combined:

x = x.rstrip('0.') # removes trailing zeroes and dots

[Peter Otten]

hanz wrote:

Or combined:

x = x.rstrip('0.') # removes trailing zeroes and dots

"130.00".rstrip ("0.")

'13'

Oops.

Peter

[py]

hanz wrote:

x = x.rstrip('0.') # removes trailing zeroes and dots

knew there had to be a way, thanks.

[Roy Smith]

In article <11************ **********@f14g 2000cwb.googleg roups.com>,
"py" <co*******@gmai l.com> wrote:

Say I have...
x = "132.00"

but I'd like to display it to be "132" ...dropping the trailing
zeros...I currently try this

This sounds to me like a job for regular expressions. Something like:

re.sub (r'\.?0*$', '', x)

will do what you want. Check out the re module in the docs for more
details.

[Matt Hammond]

On Wed, 11 Jan 2006 13:58:05 -0000, py <co*******@gmai l.com> wrote:

Say I have...
x = "132.00"

but I'd like to display it to be "132" ...dropping the trailing
zeros...

How about:

if "." in x:
x, frac = x.split(".")
frac = frac.rstrip("0" )
if frac:
x = x + "." + frac
Copes if x = "132" too. If there'll always be a decimal point, then you
can leave off the initial "if".

Matt
--

| Matt Hammond
| R&D Engineer, BBC Research & Development, Tadworth, Surrey, UK.
| http://kamaelia.sf.net/
| http://www.bbc.co.uk/rd/

[Mike Meyer]

"py" <co*******@gmai l.com> writes:

Say I have...
x = "132.00"
but I'd like to display it to be "132" ...dropping the trailing
zeros...I currently try this
The two-strip solution is cleaner, but:
if x.endswith("0") :
x = x[:len(x)-1]

x = x[:-1]
or
del x[-1]

both improve that one statement.

<mike
--
Mike Meyer <mw*@mired.or g> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.

[Peter Otten]

Mike Meyer wrote:

"py" <co*******@gmai l.com> writes:

Say I have...
x = "132.00"
but I'd like to display it to be "132" ...dropping the trailing
zeros...I currently try this

The two-strip solution is cleaner, but:

if x.endswith("0") :
x = x[:len(x)-1]

x = x[:-1]
or
del x[-1]

both improve that one statement.

del "it's tempting not to try"[-1]

Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: object doesn't support item deletion

Just-pointing-out-what-does-not-work-ly yours

Peter

[Gary Duzan]

py wrote:

x = "132.15" ...i dont want to modify it. But if
x = "132.60" ...I want it to become "132.6"

is there a better way to do this? It seems a bit ugly to me.

The following works as long as you don't mind losing leading zeros
as well:

x = x.strip('0')

Gary Duzan
Motorola CHS