Refering to the following codes I found, there is nothing displayed in the
console, may I ask why?
def thrd(param): # the thread worker function
print "Received",para m
import thread
for i in range(5): # start five threads passing i to each one
thread.start_ne w_thread(thrd,( i,))
Thanks in advance 15 1575
To be more precise, what I want to do is to have a threaded program to handle
some jobs concurrently (while those jobs are fetching information from the
Internet, so threading could speed up the process if the network is slow)
start
| (blahblahblah.. .)
v
+-----+-----+-----+-----+
| | | | |
--+-- --+-- --+-- --+-- --+--
| | | | | | | | | |
| A | | B | | C | | D | | E |
| | | | | | | | | |
--+-- --+-- --+-- --+-- --+--
| | | | |
+-----+-----+-----+-----+
| (blahblahblah.. .)
v
finish!
While process A-E will access the shared variables within the same program, and
each of those processes will have to parse a document on its own.
Valkyrie wrote: Refering to the following codes I found, there is nothing displayed in the console, may I ask why?
def thrd(param): # the thread worker function print "Received",para m
import thread for i in range(5): # start five threads passing i to each one thread.start_ne w_thread(thrd,( i,))
Thanks in advance
"Valkyrie" <va******@cuhk. edu.hk> wrote in message
news:1100875373 .911763@eng-ser6... Refering to the following codes I found, there is nothing displayed in the console, may I ask why?
def thrd(param): # the thread worker function print "Received",para m
import thread for i in range(5): # start five threads passing i to each one thread.start_ne w_thread(thrd,( i,))
You may ask, but when I tried your code, here is what happened:
Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on
win32
Type "help", "copyright" , "credits" or "license" for more information. def thrd(param): # the thread worker function
.... print "Received",para m
.... import thread for i in range(5): # start five threads passing i to each one
.... thread.start_ne w_thread(thrd,( i,))
....
1960
836
232
2864
3692 Received 0
Received 1
Received 2
Received 3
Received 4
Note that the numbers 1960, etc., appear to be the return values of the
thread.start_ne w_thread() function.
--
I don't actually read my hotmail account, but you can replace hotmail with
excite if you really want to reach me.
When I do it line by line in python's console, I have similar result to youl.
But when I try to run it in a file, say:
python demo.py
It just returns me nothing. I have no idea on this right now...
Russell Blau wrote: "Valkyrie" <va******@cuhk. edu.hk> wrote in message news:1100875373 .911763@eng-ser6...
Refering to the following codes I found, there is nothing displayed in the console, may I ask why?
def thrd(param): # the thread worker function print "Received",para m
import thread for i in range(5): # start five threads passing i to each one thread.start_ne w_thread(thrd,( i,))
You may ask, but when I tried your code, here is what happened:
Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on win32 Type "help", "copyright" , "credits" or "license" for more information.
def thrd(param): # the thread worker function ... print "Received",para m ... import thread for i in range(5): # start five threads passing i to each one ... thread.start_ne w_thread(thrd,( i,)) ... 1960 836 232 2864 3692 Received 0
Received 1 Received 2 Received 3 Received 4
Note that the numbers 1960, etc., appear to be the return values of the thread.start_ne w_thread() function.
Valkyrie wrote: Refering to the following codes I found, there is nothing displayed in the console, may I ask why?
def thrd(param): # the thread worker function print "Received",para m
import thread for i in range(5): # start five threads passing i to each one thread.start_ne w_thread(thrd,( i,))
Thanks in advance
The problem with your script is that it will run too fast before it quits and
kills all the threads.
if you add
a = 0
for i in range(100000):
a = a + 1
to the end you will see the output.
On Fri, 2004-11-19 at 23:45, Valkyrie wrote: When I do it line by line in python's console, I have similar result to youl. But when I try to run it in a file, say:
python demo.py
It just returns me nothing. I have no idea on this right now...
You need to cause the main thread to wait on the child threads until
they've all finished, otherwise - as Peter Hickman just mentioned - your
script will terminate and all threads will end. Ten seconds on Google
found this: http://www.faqts.com/knowledge_base/view.phtml/aid/1364
--
Craig Ringer
Thank you for your advice. I have quite seriously searched for it in fact, but
just without the luck on finding such article...
Craig Ringer wrote: On Fri, 2004-11-19 at 23:45, Valkyrie wrote:
When I do it line by line in python's console, I have similar result to youl. But when I try to run it in a file, say:
python demo.py
It just returns me nothing. I have no idea on this right now...
You need to cause the main thread to wait on the child threads until they've all finished, otherwise - as Peter Hickman just mentioned - your script will terminate and all threads will end. Ten seconds on Google found this:
http://www.faqts.com/knowledge_base/view.phtml/aid/1364
-- Craig Ringer
Valkyrie wrote: Thank you for your advice. I have quite seriously searched for it in fact, but just without the luck on finding such article...
Can you suggest where this information might have shown up
that you would have found it? If so, you may want to submit
a documentation bug or patch request. That is, repay the
group by making it more likely that the next person with your
problem finds their answer on their own.
--Scott David Daniels Sc***********@A cm.Org
Craig Ringer wrote: When I do it line by line in python's console, I have similar result to youl. But when I try to run it in a file, say:
python demo.py
It just returns me nothing. I have no idea on this right now...
You need to cause the main thread to wait on the child threads until they've all finished, otherwise - as Peter Hickman just mentioned - your script will terminate and all threads will end. Ten seconds on Google found this:
http://www.faqts.com/knowledge_base/view.phtml/aid/1364
Are you sure? I keep observing that child threads continue its execution
until completion even if I do nothing in main thread. Consider this example:
import random, time
from threading import Thread
class Worker(Thread):
def __init__(self, name):
Thread.__init__ (self)
self.name = name
print 'thread %s created' % self.name
def run(self):
amt = random.randint( 1, 4)
print 'thread %s waiting %d seconds' % (self.name, amt)
time.sleep(amt)
print 'thread %s finished' % self.name
def __del__(self):
print 'thread %s is being destroyed' % self.name
if __name__ == '__main__':
for i in range(10):
t = Worker('%.04d' % (i + 1, ))
t.start()
print 'finished creating threads'
Even after printing "finished creating threads" all spawned threads
continue its execution up to final "thread nnnn is being destroyed", so
I think there's no need to take any special action (unless it's Python
on iSeries, buy this is another story) to wait for completion.
--
Jarek Zgoda http://jpa.berlios.de/ | http://www.zgodowie.org/
> Even after printing "finished creating threads" all spawned threads continue its execution up to final "thread nnnn is being destroyed", so I think there's no need to take any special action (unless it's Python on iSeries, buy this is another story) to wait for completion.
The OP used the module "thread", while you used "threading" and didn't set
setDaemon(False ). Then python waits until all threads are finished.
From the thread module docs:
When the main thread exits, it is system defined whether the other threads
survive. On SGI IRIX using the native thread implementation, they survive.
On most other systems, they are killed without executing try ... finally
clauses or executing object destructors.
--
Regards,
Diez B. Roggisch This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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