Checking mail?

[Dylan Parry]

Hi,

I am by no means a Python programmer, but I am dabbling with it and trying
to create a simple program that reports how many emails I have to
download. So far, using the poplib extension, I have got:

def checkEmail():
email = poplib.POP3('ma il.mydomain.ext ')
email.user('use r')
email.pass_('pa ssword')
number = email.stat()
email.quit()

if (number[0] == 0):
return "No new emails"
elif (number[0] == 1):
return "1 new email"
else:
string = str(number[0])
string += " new emails"
return string

Which is fine as long as the server doesn't timeout, or my machine isn't
doing something else that takes up all my bandwidth! Coming from a Java
background, I was wondering if there is anything similar in Python that
allows me to do something like:

try {
something();
}
catch (exception e) {
somethingelse() ;
}

Where if the "something( )" fails then the "somethingelse( )" will be ran
instead? Or is there another way that I can deal with timeouts in Python?

Cheers,

--
Dylan Parry
http://www.webpageworkshop.co.uk - FREE Web tutorials and references

[Chris Share]

On Sat, 10 Jul 2004 12:23:08 +0100, Dylan Parry <us****@dylanpa rry.com> wrote:

try {
something();
}
catch (exception e) {
somethingelse() ;
}

I suggest you read http://www.python.org/doc/current/tut/node10.html,
and the rest of the tutorial too.

In short:

try:
code
goes
here
except FooError:
foofix()

chris

[Michal Chruszcz]

When I opened my eyes, it was Sat, 10 Jul 2004 12:23:08 +0100.
I couldn`t believe that Dylan Parry wrote:

try {
something();
}
catch (exception e) {
somethingelse() ;
}

Where if the "something( )" fails then the "somethingelse( )" will be ran
instead? Or is there another way that I can deal with timeouts in Python?

I don't know exactly how to deal with pop connections in this case, but
Python has very similar exception handling.

Read more about it at http://docs.python.org/tut/node10.html

--
_______________ _______________ _______________ _______________ ________
-=- Michal Chruszcz -=- Seen at http://prox.pl/~troll/?gallery -=-
To follow the path: look to the master, follow the master,
walk with the master, see through the master, become the master.

[Dag Hansteen]

You can do it like this:

def checkEmail():
email = poplib.POP3('ma il.mydomain.ext ')
email.user('use r')
email.pass_('pa ssword')
numbers = email.list()
count = 0
for n in numbers:
count = count + 1
print "You have", str(count), "new e-mails in inbox."
email.quit()


Best regards Dag Hansteen


----- Original Message -----
From: "Dylan Parry" <us****@dylanpa rry.com>
Newsgroups: comp.lang.pytho n
To: <py*********@py thon.org>
Sent: Saturday, July 10, 2004 1:23 PM
Subject: Checking mail?

Hi,

I am by no means a Python programmer, but I am dabbling with it and trying
to create a simple program that reports how many emails I have to
download. So far, using the poplib extension, I have got:

def checkEmail():
email = poplib.POP3('ma il.mydomain.ext ')
email.user('use r')
email.pass_('pa ssword')
number = email.stat()
email.quit()

if (number[0] == 0):
return "No new emails"
elif (number[0] == 1):
return "1 new email"
else:
string = str(number[0])
string += " new emails"
return string

Which is fine as long as the server doesn't timeout, or my machine isn't
doing something else that takes up all my bandwidth! Coming from a Java
background, I was wondering if there is anything similar in Python that
allows me to do something like:

try {
something();
}
catch (exception e) {
somethingelse() ;
}

Where if the "something( )" fails then the "somethingelse( )" will be ran
instead? Or is there another way that I can deal with timeouts in Python?

Cheers,

--
Dylan Parry
http://www.webpageworkshop.co.uk - FREE Web tutorials and references
--
http://mail.python.org/mailman/listinfo/python-list

[Cameron Laird]

In article <ma************ *************** **********@pyth on.org>,
Dag Hansteen <d-*****@online.no > wrote:

[Dylan Parry]

Dylan Parry wrote:

Thanks to all that replied. I have since read the tutorial pointed out,
and it seems to be exactly what I was looking for. Thanks again ;)

--
Dylan Parry
http://www.webpageworkshop.co.uk - FREE Web tutorials and references