get "yesterday' s" date in iso format

[necromancer_stupidspambot]

Hi,

I am trying to find a simple way to get "yesterday' s" date. I know I can
build various check to seee if we are in leap year, if we are the 1st then
yesterday is the 31(or 30 depending of the month) etc. but there is got to
be a simpler way than that. I was thinking of using the gmtime (field 7 as
you can see int the code)then substract one, then use strptime to rebuild
the time but it doesn't work(probably because I misunderstood strptime):

improt time
gmt = time.gmtime()
yesterdaytime = str(int(gmt[7]) - 1)
print gmt[7]
print yesterdaytime
newtime = time.strptime(y esterdaytime,'% j')
print newtime
(1900, 1, 22, 0, 0, 0, 0, 22, -1)

can someone enlighten me please?

Thanks
David

[Ben Finney]

On Thu, 22 Jan 2004, ne************* **********@quan ta...dspambo t.com wrote:

I am trying to find a simple way to get "yesterday' s" date.

import datetime
today = datetime.date.t oday()
today datetime.date(2 004, 1, 23) yesterday = today - datetime.timede lta( 1 )
yesterday

datetime.date(2 004, 1, 22)

--
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Ben Finney <http://bignose.squidly .org/>

[Tim Heaney]

ne************* **********@quan ta...dspambo t.com writes:

I am trying to find a simple way to get "yesterday' s" date. I know I can
build various check to seee if we are in leap year, if we are the 1st then
yesterday is the 31(or 30 depending of the month) etc. but there is got to
be a simpler way than that.

Since time.time() gives the time in seconds since the epoch, you could
just subtract a day from that to get yesterday.

import time
time.gmtime(tim e.time()-24*60*60)

(2004, 1, 22, 4, 36, 3, 3, 22, 0)

I hope this helps,

Tim

[Gerrit Holl]

Tim Heaney wrote:

ne************* **********@quan ta...dspambo t.com writes:

I am trying to find a simple way to get "yesterday' s" date.

Since time.time() gives the time in seconds since the epoch, you could
just subtract a day from that to get yesterday.

Even better:

from datetime import date, timedelta
(date.today() - timedelta(1)).d ay

22

yours,
Gerrit.

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[necromancer_stupidspambot]

On Fri, 23 Jan 2004 17:54:15 +0100, Gerrit Holl wrote:

Tim Heaney wrote:

ne************* **********@quan ta...dspambo t.com writes:

>
> I am trying to find a simple way to get "yesterday' s" date.

Since time.time() gives the time in seconds since the epoch, you could
just subtract a day from that to get yesterday.

Even better:

from datetime import date, timedelta
(date.today() - timedelta(1)).d ay

22

Excellent. I guess I skipped the timedela section of the datetime module.

Thanks a lot,
David