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sleep() function, perhaps.


Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".

[code]
import time

sleep(.5)
print "."
sleep(.5)
print "."
[end code]

But, it would (with those .5 second intervals)
print out much like the following.

..
(pause)
..
(pause)

I would rather those periods be on a single line, not printing on a new
line each time.

Any suggestions?

Thank you in advance,
~Ryan

Jul 18 '05 #1
12 5694
"Ryan Spencer" <je***@earthlin k.net> schrieb im Newsbeitrag
news:pa******** *************** *****@earthlink .net...
|
| Hello Everyone,
|
| I want to have a row of periods, separated by small, say, .5 second
| intervals between each other. Thus, for example, making it have the
| appearance of a progress "bar".
|
| [code]
| import time
|
| sleep(.5)
| print "."
| sleep(.5)
| print "."
| [end code]
|
| But, it would (with those .5 second intervals)
| print out much like the following.

|
| .
| (pause)
| .
| (pause)
|
| I would rather those periods be on a single line, not printing on a new
| line each time.

import time,sys

while 1:
sys.stdout.writ e(".")
time.sleep(0.5)

You could also use:

print ".",

(note the trailing comma)

but that will leave you with an additional space after the dot

HTH,

Vincent Wehren
| Any suggestions?
|
| Thank you in advance,
| ~Ryan
|
Jul 18 '05 #2
On Tue, 25 Nov 2003 05:26:25 GMT, Ryan Spencer <je***@earthlin k.net>
wrote:

Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".

[code]
import time

sleep(.5)
print "."
sleep(.5)
print "."
[end code]

But, it would (with those .5 second intervals)
print out much like the following.

.
(pause)
.
(pause)

I would rather those periods be on a single line, not printing on a new
line each time.

Any suggestions?


Try print with added comma or sys.stdout.writ e, like so:
import time
for i in range(10): .... print '\b.',
.... time.sleep(1.5)
....
........... import sys
for i in range(10):

.... sys.stdout.writ e('.')
.... time.sleep(0.5)
....
...........
--
Christopher
Jul 18 '05 #3
On Tue, 25 Nov 2003 06:14:20 +0000, Christopher Koppler wrote:
On Tue, 25 Nov 2003 05:26:25 GMT, Ryan Spencer <je***@earthlin k.net>
wrote:

Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".

[code]
import time

sleep(.5)
print "."
sleep(.5)
print "."
[end code]

But, it would (with those .5 second intervals)
print out much like the following.

.
(pause)
.
(pause)

I would rather those periods be on a single line, not printing on a new
line each time.

Any suggestions?


Try print with added comma or sys.stdout.writ e, like so:
import time
for i in range(10): ... print '\b.',
... time.sleep(1.5)
...
.......... import sys
for i in range(10):

... sys.stdout.writ e('.')
... time.sleep(0.5)
...
..........

Heya', Thanks,

Actually though, None of those suggestions give me the desired result
I was looking for. I used both with the for loops, even the one with the
while loop, and for the first suggested it prints all of them out on new
lines (as opposed to all on the same line as I'd been hoping for) and the
second posts on one full line, yet, the periods still don't have pauses
between themselves. Perhaps something else is amiss?

As well, the trailing commas gives the exact same result as doing the
sys.stdout.writ e function.

Is the code that you suggested giving you a result such as...

..(pause).(paus e).(pause).

I raised everything up to a 1.5 second interval to exaggerate the results,
and I'm afraid I still don't notice the pauses.

Perchance I simply need to remove whatever is terminating the line?
Does the time.sleep() function itself terminate a line? It would seem
if I could bypass that, it would allow the pauses and keep the periods
on one line.

Thank you for your advice though, It's highly appreciated.

~Ryan
Jul 18 '05 #4
>>>>> "Ryan" == Ryan Spencer <je***@earthlin k.net> writes:

Ryan> On Tue, 25 Nov 2003 06:14:20 +0000, Christopher Koppler wrote:
On Tue, 25 Nov 2003 05:26:25 GMT, Ryan Spencer <je***@earthlin k.net>
wrote:
Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".

[code] import time

sleep(.5) print "." sleep(.5) print "." [end code]

But, it would (with those .5 second intervals) print out much like
the following.

. (pause) . (pause)

I would rather those periods be on a single line, not printing on a
new line each time.

Any suggestions?

Try print with added comma or sys.stdout.writ e, like so:
> import time for i in range(10):

... print '\b.', ... time.sleep(1.5) ... ..........
> import sys for i in range(10):

... sys.stdout.writ e('.') ... time.sleep(0.5) ... ..........

Ryan> Heya', Thanks,

Ryan> Actually though, None of those suggestions give me the desired
Ryan> result I was looking for. I used both with the for loops, even the
Ryan> one with the while loop, and for the first suggested it prints all
Ryan> of them out on new lines (as opposed to all on the same line as
Ryan> I'd been hoping for) and the second posts on one full line, yet,
Ryan> the periods still don't have pauses between themselves. Perhaps
Ryan> something else is amiss?

Ryan> As well, the trailing commas gives the exact same result as doing
Ryan> the sys.stdout.writ e function.

Ryan> Is the code that you suggested giving you a result such as...

Ryan> .(pause).(pause ).(pause).

Ryan> I raised everything up to a 1.5 second interval to exaggerate the
Ryan> results, and I'm afraid I still don't notice the pauses.

Ryan> Perchance I simply need to remove whatever is terminating the
Ryan> line? Does the time.sleep() function itself terminate a line? It
Ryan> would seem if I could bypass that, it would allow the pauses and
Ryan> keep the periods on one line.

Ryan> Thank you for your advice though, It's highly appreciated.

Without a newline character, the normal sys.stdout writes to a buffer and
won't try to flush it out. Try this:
for i in range(10):

.... sys.stdout.writ e('.')
.... sys.stdout.flus h()
.... time.sleep(.5)
....
...........>>>

Regards,
Isaac.
Jul 18 '05 #5
Ryan Spencer wrote:
Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".


You've got the answer for dots, here's a spinner in case it's useful:

import sys, time

spinner="|/-\\"
pos=0

while 1:
sys.stdout.writ e("\r"+spinne r[pos])
sys.stdout.flus h()
time.sleep(.5)
pos+=1
pos%=4

Jul 18 '05 #6

Ryan> I want to have a row of periods, separated by small, say, .5
Ryan> second intervals between each other. Thus, for example, making it
Ryan> have the appearance of a progress "bar".

You might find my progress module at

http://www.musi-cal.com/~skip/python/progress.py

a good starting point. Something like

import progress, time
ticker = progress.Progre ss(major=1, minor=1, majormark='.')
while True:
ticker.tick()
time.sleep(0.5)

running in a separate thread should do what you want.

In many situations you want to actually measure progress of some
computation. If you can wedge in a call to ticker.tick() on each pass of
your main computation loop:

import progress, time
ticker = progress.Progre ss()
while some_condition_ holds:
one_more_comput ational_step()
ticker.tick()

you can watch your computation progress.

This is particularly helpful if you know how many passes you need to make
around the loop:

import progress, time
number_of_passe s = 10000
ticker = progress.Progre ss(title="(%d)" % number_of_passe s)
for i in xrange(number_o f_passes):
one_more_comput ational_step()
ticker.tick()

The title displayed tells you how many loops to expect and the dots and
numbers measure your progress:

(10000): .........1..... ....2.........3 .........4

and when you delete the ticker or it goes out-of-scope, it displays the
total number of ticks (which might be lower if the loop was exited
prematurely).

There are more bells and whistles. Check the Progress class docstring for
full details.

Skip

Jul 18 '05 #7
Pa*****@Linux.i e wrote:

Ryan Spencer wrote:
Hello Everyone,

I want to have a row of periods, separated by small, say, .5 second
intervals between each other. Thus, for example, making it have the
appearance of a progress "bar".


You've got the answer for dots, here's a spinner in case it's useful:

import sys, time

spinner="|/-\\"
pos=0

while 1:
sys.stdout.writ e("\r"+spinne r[pos])
sys.stdout.flus h()
time.sleep(.5)
pos+=1
pos%=4


And a quicky OO version for kicks (untested):

class Spinner:
CHARS = r"|/-\"
def __init__(self, stream=sys.stdo ut):
self.index = 0
self.stream = stream
def spin(self):
self.stream.wri te('\r' + self.CHARS[self.index])
self.stream.flu sh()
self.index = (self.index + 1) % len(CHARS)

spin = Spinner()
while 1:
spin.spin()
time.sleep(0.5)

-Peter
Jul 18 '05 #8
Peter Hansen wrote:
And a quicky OO version for kicks (untested):

class Spinner:
CHARS = r"|/-\"
Python chokes when it encounters an odd number of backslashes at the end of
a raw string.
def __init__(self, stream=sys.stdo ut):
self.index = 0
self.stream = stream
def spin(self):
self.stream.wri te('\r' + self.CHARS[self.index])
self.stream.flu sh()
self.index = (self.index + 1) % len(CHARS)


Whenever you have to calculate an index, look into the itertools module
first; so here's my variant (2.3 only):

class Spinner:
def __init__(self, stream=sys.stdo ut, chars="|/-\\"):
self.cycle = itertools.cycle (["\r" + c for c in chars])
self.stream = stream
def spin(self):
self.stream.wri te(self.cycle.n ext())
self.stream.flu sh()

Peter
Jul 18 '05 #9
Peter Otten wrote:

Peter Hansen wrote:
And a quicky OO version for kicks (untested):

class Spinner:
CHARS = r"|/-\"
Python chokes when it encounters an odd number of backslashes at the end of
a raw string.


Good point. In that case, I'd prefer to re-order rather than
using the \\ form, as I (personally) find that somewhat unreadable
for short strings where each character is treated separately (as
is often the case with regex patterns, for example, or the above).
Whenever you have to calculate an index, look into the itertools module
first; so here's my variant (2.3 only):

class Spinner:
def __init__(self, stream=sys.stdo ut, chars="|/-\\"):
self.cycle = itertools.cycle (["\r" + c for c in chars])
self.stream = stream
def spin(self):
self.stream.wri te(self.cycle.n ext())
self.stream.flu sh()


Nice... someday I'll have to find time to look at that itertools module,
I guess. :-)

-Peter
Jul 18 '05 #10

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