Problems with conversion of values in strings to integers

[Jørgen Cederberg]

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.

int('-10') -10 int('10') 10 int(10.1) 10 int('10.1') Traceback (most recent call last):
File "<stdin>", line 1, in ?
ValueError: invalid literal for int(): 10.1

This is quite frustating. The only solution I can see is to do: int(float('10.1 '))

10

Is this the only solution or are there any other way to do this?

Regards
Jorgen Cederberg

[Karl Scalet]

Jørgen Cederberg wrote:

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.

>>> int('-10') -10 >>> int('10') 10 >>> int(10.1) 10 >>> int('10.1') Traceback (most recent call last):
File "<stdin>", line 1, in ?
ValueError: invalid literal for int(): 10.1

This is quite frustating. The only solution I can see is to do: >>> int(float('10.1 ')) 10

depending on what you actually want,

int(round('10.1 '))

might be appropriate.
But if you really want the "floor"-value,
nothing is wrong with your approach.

Karl

[Peter Otten]

Jørgen Cederberg wrote:

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.

>>> int('-10') -10 >>> int('10') 10 >>> int(10.1) 10 >>> int('10.1') Traceback (most recent call last):
File "<stdin>", line 1, in ?
ValueError: invalid literal for int(): 10.1

This is quite frustating. The only solution I can see is to do: >>> int(float('10.1 ')) 10

Is this the only solution or are there any other way to do this?

There is more than one way to convert a string representing a fp number to
an integer:

int(float("1.99 9")) 1
int(round(float ("1.999")))

2

I think it's good that Python does not make the decision for you. Once you
have decided which route to go you can easily wrap it into a helper
function, e. g.

def toInt(s):
try:
return int(s)
except ValueError:
return int(round(float (s)))

(When dealing with user input, things are a little more complicated, as the
decimal separator changes between locales)

Peter

[Jørgen Cederberg]

Peter Otten wrote:

Jørgen Cederberg wrote:

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.
<snip examples of converting strings with int()>

This is quite frustating. The only solution I can see is to do:

>>> int(float('10.1 '))

10

Is this the only solution or are there any other way to do this?

There is more than one way to convert a string representing a fp numberto
an integer:
int(float("1.99 9")) 1
int(round(float ("1.999")))

2

I think it's good that Python does not make the decision for you. Once you
have decided which route to go you can easily wrap it into a helper
function, e. g.

def toInt(s):
try:
return int(s)
except ValueError:
return int(round(float (s)))

(When dealing with user input, things are a little more complicated, asthe
decimal separator changes between locales)

Thanks a lot for the function. It solves the problem elegantly.

/Jorgen

[Bengt Richter]

On Mon, 06 Oct 2003 14:06:26 +0200, Peter Otten <__*******@web. de> wrote:

Jørgen Cederberg wrote:

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.

>>> int('-10') -10

>>> int('10')

10

>>> int(10.1)

10

>>> int('10.1')

Traceback (most recent call last):
File "<stdin>", line 1, in ?
ValueError: invalid literal for int(): 10.1

This is quite frustating. The only solution I can see is to do:

>>> int(float('10.1 '))

10

Is this the only solution or are there any other way to do this?

There is more than one way to convert a string representing a fp number to
an integer:

Indeed, but what if the OP wants something like C's atoi? E.g.,
(playing with MinGW and MSYS -- pretty neat, BTW ;-)

[14:35] /c/pywk/clp/atoi>cat pratoi.c
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]){
if(argc<2){
printf("Usage: pratoi strings ...\n");
} else {
int i;
char sbuf[32];
for(i=1;i<argc; ++i){
snprintf(sbuf,3 2,"'%s'",argv[i]);
printf("%8s => %d\n", sbuf, atoi(argv[i]));
}
}
return 0;
}
[14:35] /c/pywk/clp/atoi>gcc pratoi.c -o pratoi
[14:35] /c/pywk/clp/atoi>pratoi 0 1 -1 +1 123 4.5 -5.6 -1.2e3 0x11 011 " -3xx" " -xx"
'0' => 0
'1' => 1
'-1' => -1
'+1' => 1
'123' => 123
'4.5' => 4
'-5.6' => -5
'-1.2e3' => -1
'0x11' => 0
'011' => 11
' -3xx' => -3
' -xx' => 0

Note the 'way different result on -1.2e3 in particular. Also does the OP want to ignor
octal and hex or reject them?

atoi looks like it just strips leading spaces, takes and optional sign, and computes
a decimal from as many decimal digits as it can then find (including none as ok).

I'll leave that as an exercise for python ;-)

int(float("1.99 9"))1
int(round(float ("1.999")))

2

I think it's good that Python does not make the decision for you. Once you
have decided which route to go you can easily wrap it into a helper
function, e. g.

def toInt(s):
try:
return int(s)
except ValueError:
return int(round(float (s)))

(When dealing with user input, things are a little more complicated, as the
decimal separator changes between locales)

There's that too ;-)

Regards,
Bengt Richter

[Jørgen Cederberg]

Bengt Richter wrote:

On Mon, 06 Oct 2003 14:06:26 +0200, Peter Otten <__*******@web. de> wrote:

Jørgen Cederberg wrote:

Hi,

using Python 2.2.1 on Windows and QNX I'm having trouble understandig
why int() raises a ValueError exception upon converting strings.
<snip example of converting strings/floats with int()>
This is quite frustating. The only solution I can see is to do:
>>> int(float('10.1 '))
10

Is this the only solution or are there any other way to do this?

<snip - atoi example>

> int(float("1.99 9"))

1

> int(round(float ("1.999")))

2

I think it's good that Python does not make the decision for you. Once you
have decided which route to go you can easily wrap it into a helper
function, e. g.

def toInt(s):
try:
return int(s)
except ValueError:
return int(round(float (s)))

(When dealing with user input, things are a little more complicated, asthe
decimal separator changes between locales)

There's that too ;-)

Actually my problem arose using the Scale widget in Tkinter. The small
program below demonstrates the problem.

The first line with Scale doesn't work, as the IntVar(!), tries to
convert a string from Tkinter, that is in fact a float. This results
from the Tkinter function getint, which is the same as int.

--------------------------
from Tkinter import *

def onScale(value):
print "The value is", value,"and its type is", type(value)
print "The variable is", var.get(),"and its type is", type(var.get())

root = Tk()
var = IntVar()

# This does'nt work. The value inside the Scale is now a float
represented in
# string, which int() can't handle.
#s = Scale(root, length=100, bd=1, digit=3, from_ = -10,
#to=10,variable =var, command=onScale )

# This works.
s = Scale(root, length=100, bd=1, from_ = -10, to=10,variable= var,
command=onScale )
s.pack()

root.mainloop()
--------------------------

One might argue that it doesn't make sense to use the Scale with digits
together with an IntVar, but in my case to from_ and to values can both
be integers and floats.

Regards
Jorgen