Thor <th******@yahoo .com> wrote in
news:bh******** ****@ID-108351.news.uni-berlin.de:
In this hypothetical case:
def f1:
f3:
def f2:
def f3:
pass
f1:
def f4:
def f3:
pass
f1:
would the function f1 execute the right f3 depending on from which
functions is it called?
Why don't you load up the interactive interpreter and try running it?
You'll find a lot of mistakes in the hypothetical code you entered,
including the absence of argument lists after the function names, and the
spurious colons and lack of parenthese on the function calls.
I'll assume you actually meant something like:
def f1():
f3()
def f2():
def f3():
pass
f1()
def f4():
def f3():
pass
f1()
If the code above is indeed what you intended then calling either f2() or
f4() will result in a 'NameError' exception because there is no name 'f3'
in scope from inside f1(). There are local variables 'f3' inside both f2()
and f4(), but local variables are never visible nor accessible from outside
the functions in which they are defined. (They are visible from inside
nested functions, but that is not the situation here.)
To get code something like this to work, you should pass f3 as a parameter
to f1:
def f1(f3):
f3()
def f2():
def f3():
pass
f1(f3)
def f4():
def f3():
pass
f1(f3)
Remember, Python functions are just objects like any other and may be
assigned to variables or passed in and out of other functions.
--
Duncan Booth
du****@rcp.co.u k
int month(char *p){return(1248 64/((p[0]+p[1]-p[2]&0x1f)+1)%12 )["\5\x8\3"
"\6\7\xb\1\x9\x a\2\0\4"];} // Who said my code was obscure?
