Isn't there an easier way than
lst[len(lst) - 1] = ...
? 57 41873
Or alternatively:
Is there a way to make reference to the last element of a list, to use
as a shorthand:
ref := &lst[len(lst) - 1] # I know syntax is wrong, but you get the
idea
and then using the last element of the list by (assuming the element is
a dict):
ref["foo"] = 42
ref["bar"] = "Ni!"
etc.
/David
Aloha, pi************@ gmail.com wrote: Isn't there an easier way than lst[len(lst) - 1] = ...
lst[-1] = ...
Wishing a happy day
LOBI
I knew there was an easy way :)
Just to satisfy my curiousity: Is there a way to do something like the
reference solution I suggest above? pi************@ gmail.com wrote: Just to satisfy my curiousity: Is there a way to do something like the reference solution I suggest above?
No. You cannot overload assignment.
Of course, for mutable objects you can use the object as the "reference" to
itself.
Peter
Peter Otten wrote: pi************@ gmail.com wrote:
Just to satisfy my curiousity: Is there a way to do something like the reference solution I suggest above?
No. You cannot overload assignment.
I have the impression that this is not an issue, to overload assignments,
which btw. *can* be overloaded, but the absence of *aliasing* (undiscriminate
handling of pointers) in Python. Am I wrong?
Jerzy Karczmarczuk
So there is no way in Python to make an alias for an object?
/David
what do you mean by alias ?
a = b
now both a and b refers to the same object. pi************@ gmail.com wrote: So there is no way in Python to make an alias for an object?
/David
I just want an alias. Ideally, I don't want to deal with pointers or
special reference "types" etc. After all, this is not C++ :)
I just want to be able to make a reference to any old thing in Python.
A list, an integer variable, a function etc. so that I, in complicated
cases, can make a shorthand. If "myRef" could somehow "point at"
something long an complicated like a[42]["pos"][-4], that might be
useful.
/David
But if lst[42]["pos"] happens to hold an integer value, then
a = lst[42]["pos"]
will _copy_ that integer value into 'a', right? Changing 'a' will not
change the value at lst[42]["pos"] This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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