ghjk  250
Contributor
I want to use two drop down menus in my php application. All data should select from the database(Mysql) . Eg: 1st drop down(Fruit,Coun try,game) after selecting a item from the first drop down , second one should load perticular data from tha database. If i select Fruit then automatically load Mango,banana.et c to the second drop down. Could you please help me?
5 3584 
We are here to help programmers with their PHP problems. And we can only help when we can see and work on the code you have developed.
So show it here and do not forget to enclose any code within the appropriate code tags!
Ronald
ghjk 250
Contributor
We are here to help programmers with their PHP problems. And we can only help when we can see and work on the code you have developed.
So show it here and do not forget to enclose any code within the appropriate code tags!
Ronald
This is my first dropdown(Thease are hard coded. no need to select from the database)
[HTML]<select name="name" id="name" >
<option value="Select" selected="selec ted">Select</option>
<option value="Fruit" >Fruit</option>
<option value="Country" >Country</option>
<option value="Game"> Game</option>
</select> [/HTML]
And second drop down should filled depend on the selected value in first dropdown.(get values from mysql database)
-
<!--
-
----------------------------
-
here i juz worked in a localhost.
-
database: demo1;
-
table: demo_table;
-
fields(demo_table)
-
item varchar(20);
-
list varchar(20);
-
example table data( i here used a simple table structure u can use a well one):
- item list
-
fruit Mango
-
fruit banana
-
Country India
-
Country USA
-
Country UK
-
----------------------------
-
-->
-
<html>
-
<head>
-
<title></title>
-
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
-
<script type="text/javascript">
-
function getItem(sel)
-
{
-
var itemCode = sel.options[sel.selectedIndex].value;
-
//alert(itemCode);
-
var url= "http://localhost/onchange1.php?item="+itemCode;
-
window.location=url;
-
-
}
-
</script>
-
</head>
-
-
<body>
-
-
<form action="" method="post">
-
<table>
-
<tr>
-
<td>Item </td>
-
<td><select id="item" name="item" onchange="getItem(this)">
-
<option value="">Select </option>
-
<option value="Fruit">Fruit</option>
-
<option value="Country" >Country</option>
-
</select>
-
</td>
-
</tr>
-
<tr>
-
<td>List </td>
-
<td><select id="item_list" name="item_list" >
-
<option value="">Select </option>
-
<?php
-
$i_code=$_REQUEST['item'];
-
-
$con = mysql_connect("localhost","root","");
-
mysql_select_db("demo1",$con);
-
-
$query="select list from demo_table where item='$i_code'";
-
$res=mysql_query($query);
-
$num=mysql_num_rows($res);
-
for($i=0;$i<$num;$i++)
-
{
-
$data=mysql_fetch_array($res);
-
$v=$data[0].$i;
-
echo "<option value='$data[0]'>".$data[0]."</option>";
-
}
-
?>
-
</select>
-
</td>
-
</tr>
-
</table>
-
</form>
-
</body>
-
</html>
-
it is a simplest method, and also u can use AJAX.
Atli 5,058
Recognized Expert Expert
Hi sethupnr.
Please use [code] tags when posting your code examples. (See How to ask a question)
[code=html] ...HTML code goes here... [/code]
Thank you.
i have categories,then under each category,i want a sub category,all from database for example,categor y sells,then sub items and this is a menue in an html page from database,can u help plz
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