Is there any support for a negative condition in If statements in PHP.
Some tutorials ive found say that you can use the if!(condition)c md;
syntax. however i always get an error when i use that.
"Parse error: parse error, unexpected '!', expecting '(' in
TMP5rsqwh3ag.ph p on line 13"
I am runing PHP 4.3.2.
Regards
Tristan
4  108448 
"Tristan" <tr************ @hotmail.com> wrote in message
news:3d******** *************** ***@posting.goo gle.com... Is there any support for a negative condition in If statements in PHP.
Some tutorials ive found say that you can use the if!(condition)c md;
syntax. however i always get an error when i use that.
"Parse error: parse error, unexpected '!', expecting '(' in
TMP5rsqwh3ag.ph p on line 13"
I am runing PHP 4.3.2.
Regards
Tristan
<?php
$test="blah";
if(!$test=="tes t")print "test ain't test";
?>
remember, you need double = sign when testing this condition, or you'll end
up looking for a needle in a haystack. a single = first assigns the word
"test" to the variable and then tests the condition, resulting in a double
negative in this case.
Mich
Tristan wrote: Is there any support for a negative condition in If statements in PHP.
Unlike the subject, the correct syntax is (replace NOT with !)
if (NOT condition)
Examples
if (!$done) continue;
if (!preg_match('/hello/', $text)) echo "Please say hello.";
if (!((1 <= $qty) && ($qty <= 99))) echo "Please enter 1 to 99 only.";
Some tutorials ive found say that you can use the if!(condition)c md;
syntax. however i always get an error when i use that.
That is wrong. Please inform the authors of those tutorials they have a
syntax error in their code. Should be
if (!condition) cmd;
--
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Danke for that. I went back to the original Tutorial and found it was
a Typo on their half which had thrown me.
"michel" <no@spam.please > wrote in message news:<cc******* ***@news.cistro n.nl>... "Tristan" <tr************ @hotmail.com> wrote in message
news:3d******** *************** ***@posting.goo gle.com... Is there any support for a negative condition in If statements in PHP.
Some tutorials ive found say that you can use the if!(condition)c md;
syntax. however i always get an error when i use that.
"Parse error: parse error, unexpected '!', expecting '(' in
TMP5rsqwh3ag.ph p on line 13"
I am runing PHP 4.3.2.
Regards
Tristan
<?php
$test="blah";
if(!$test=="tes t")print "test ain't test";
?>
remember, you need double = sign when testing this condition, or you'll end
up looking for a needle in a haystack. a single = first assigns the word
"test" to the variable and then tests the condition, resulting in a double
negative in this case.
Mich
Tristan schrieb: "Parse error: parse error, unexpected '!', expecting '(' in
TMP5rsqwh3ag.ph p on line 13"
simple: you wrote 'if !(...' instead of 'if (!... -- as you said, a typo., This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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