Checking if var is integer string or int

[Jim]

Hi guys,

The variable '$pixels' in the code below may be an integer type or an
integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?

if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code
}

Thanks,

Jimmy.

[ZeldorBlat]

On Apr 23, 2:27 pm, Jim <[e-mail] wrote:

Hi guys,

The variable '$pixels' in the code below may be an integer type or an
integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?

if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code

}

Thanks,

Jimmy.

Why not just

if(!ctype_digit ($pixels))

?

[Jim]

The variable '$pixels' in the code below may be an integer type or an

integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?

if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code

}

Why not just

if(!ctype_digit ($pixels))

?

Because if I pass in an integer type e.g. ctype_digit(35) it returns
false as it converts 35 to the characters set equivalent (# symbol in
my case) .

Jimmy.

[gosha bine]

On 24.04.2007 10:00 Jim wrote:

>>The variable '$pixels' in the code below may be an integer type or an
integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?
if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code
}

>Why not just

if(!ctype_digi t($pixels))

?

Because if I pass in an integer type e.g. ctype_digit(35) it returns
false as it converts 35 to the characters set equivalent (# symbol in
my case) .

Jimmy.

Use typecast then

if(ctype_digit( (string)$var))
var is an int

or

if(ctype_digit( "$var"))
var is an int
another possibility, without function calls:

if((string)(int )$var === (string)$var)
var is an int
--
gosha bine

extended php parser ~ http://code.google.com/p/pihipi
blok ~ http://www.tagarga.com/blok

[Jim]

Use typecast then

>
if(ctype_digit( (string)$var))
var is an int

or

if(ctype_digit( "$var"))
var is an int

another possibility, without function calls:

if((string)(int )$var === (string)$var)
var is an int

Can't do that as a non-numeric string will be cast to 0 and therefore
won't be correctly validated.

Jimmy.

[gosha bine]

On 27.04.2007 11:48 Jim wrote:

>Use typecast then

if(ctype_digit ((string)$var))
var is an int

or

if(ctype_digit ("$var"))
var is an int

another possibility, without function calls:

if((string)(in t)$var === (string)$var)
var is an int

Can't do that as a non-numeric string will be cast to 0 and therefore
won't be correctly validated.

Exactly, it's converted to 0 and thus causes test to fail, i.e.
non-numeric string is not a number, QED.
--
gosha bine

extended php parser ~ http://code.google.com/p/pihipi
blok ~ http://www.tagarga.com/blok

[Bocah Sableng]

On Apr 24, 1:27 am, Jim <[e-mail] wrote:

Hi guys,

The variable '$pixels' in the code below may be an integer type or an
integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?

if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code

}

How about is_numeric() ?

$pixels_numeric = 25;
$pixels = '25';
var_dump($pixel s);
var_dump($pixel s_numeric);
var_dump(is_num eric($pixels));
var_dump(is_num eric($pixels_nu meric));
var_dump(!ctype _digit($pixels) );
var_dump(!ctype _digit($pixels_ numeric));
var_dump(!is_in t($pixels) && !ctype_digit($p ixels));
var_dump(!is_in t($pixels_numer ic) && !ctype_digit($p ixels_numeric)) ;

HTH

[Bocah Sableng]

On Apr 27, 7:00 pm, Bocah Sableng <cahsabl...@gma il.comwrote:

On Apr 24, 1:27 am, Jim <[e-mail] wrote:

Hi guys,

The variable '$pixels' in the code below may be an integer type or an
integer represented as a string type. I need to check if the value is
indeed one of these. Is the following code the simplest I can get?

if (!is_int($pixel s) && !ctype_digit($p ixels))
{
// some code

}

How about is_numeric() ?

$pixels_numeric = 25;
$pixels = '25';
var_dump($pixel s);
var_dump($pixel s_numeric);
var_dump(is_num eric($pixels));
var_dump(is_num eric($pixels_nu meric));
var_dump(!ctype _digit($pixels) );
var_dump(!ctype _digit($pixels_ numeric));
var_dump(!is_in t($pixels) && !ctype_digit($p ixels));
var_dump(!is_in t($pixels_numer ic) && !ctype_digit($p ixels_numeric)) ;

HTH

Oops.. too quick to respond.
Sorry for that. :(