Checking param string

[david]

Code:
#include <stdio.h>
#include <strings.h>
#include <stdlib.h>

int main (int argc, char const *argv[])
{
if (argc == 1)
printf("No parameters! Use --help to get more information.");

if (argc == 2 && argv[1] == "--help")
printf("Just test, you are free now.");

if (argv[1][0] == "-")
printf("This does not work?");

return 0;
}

Two questions:
1) How can I compare parameters to string, maybe I should use sprintf
and later try comparing? Or maybe there is direct way of doing it?
2) How can I get first char of the first parameter? (It's kinda hard
to understand how to write this)

Using gcc 4 version under Mac OS X.

[Malcolm McLean]

"david" <Da************ *****@gmail.com wrote in message
news:17******** *************** ***********@60g 2000hsy.googleg roups.com...

Code:
#include <stdio.h>
#include <strings.h>
#include <stdlib.h>

int main (int argc, char const *argv[])
{
if (argc == 1)
printf("No parameters! Use --help to get more information.");

if (argc == 2 && argv[1] == "--help")
printf("Just test, you are free now.");

if (argv[1][0] == "-")
printf("This does not work?");

return 0;
}

Two questions:
1) How can I compare parameters to string, maybe I should use sprintf
and later try comparing? Or maybe there is direct way of doing it?
2) How can I get first char of the first parameter? (It's kinda hard
to understand how to write this)

The compiler should give you a warning for the second and last. You are
comparing a character to a string. You need '-' to create a char constant,
strcmp() to compare
if( strcmp(argv[1], "-help") == 0)
{

}
When you've sorted this out you might like to see my options parser, on the
website.
--
Free games and programming goodies.
http://www.personal.leeds.ac.uk/~bgy1mm

[david]

I understood the problem with string comparison, but how about the
last if, which makes gcc to give me warning: testas.c:13: warning:
comparison between pointer and integer

Can I access the certain char of that parameter or I should use some
strings commands to make this work?
argv[1] is a pointer to the char array in memory, *argv[1] should show
to the first char in that array, the same as *argv[1][0]. I am right
(It looks that I am not)

david

P.S. Thanks for the help.

[Ben Bacarisse]

david <Da************ *****@gmail.com writes:

I understood the problem with string comparison, but how about the
last if, which makes gcc to give me warning: testas.c:13: warning:
comparison between pointer and integer

The code is:

if (argv[1][0] == "-")
printf("This does not work?");

(you should quote enough to give context)

Can I access the certain char of that parameter or I should use some
strings commands to make this work?

You can get at the characters one by one if you like as arg[1][0] and
argv[1][1] etc. The error is with the "-" which is a string literal,
not a character. Use '-'.

argv[1] is a pointer to the char array in memory, *argv[1] should show
to the first char in that array, the same as *argv[1][0]. I am right
(It looks that I am not)

The last one is not right but *argv[1] is OK. *argv[1][0] is trying
to apply * to character (namely argv[1][0]).

--
Ben.

[Kenny McCormack]

In article <db************ *************** *******@q70g200 0hsb.googlegrou ps.com>,
david <Da************ *****@gmail.com wrote:

>I understood the problem with string comparison, but how about the
last if, which makes gcc to give me warning: testas.c:13: warning:
comparison between pointer and integer

Can I access the certain char of that parameter or I should use some
strings commands to make this work?
argv[1] is a pointer to the char array in memory, *argv[1] should show
to the first char in that array, the same as *argv[1][0]. I am right
(It looks that I am not)

david

P.S. Thanks for the help.

I suggest you switch to a more friendly language, such as AWK.
(Where this sort of nonsense doesn't happen)

[david]

I can't switch (studying Software Engineering). I just started to
learn C and C++ and difference between them.
C looks a bit familiar to ASM after some time, but I still don't know
this well enough for now, but that should change in month or two. But
I still think that ASM is better for now (for small code, like base64,
crc and etc programs/code fragments)

[david]

I know about the else, I just wrote it for small example not thinking
much about if statements. Next time (if there will be one I will try
not to do this and write as much correct code as I can).

I am reading this group from Google, there could I find FAQ of this
group?

[Flash Gordon]

Malcolm McLean wrote, On 20/02/08 18:00:

>
"david" <Da************ *****@gmail.com wrote in message
news:17******** *************** ***********@60g 2000hsy.googleg roups.com...

>Code:
#include <stdio.h>
#include <strings.h>
#include <stdlib.h>

int main (int argc, char const *argv[])
{
if (argc == 1)
printf("No parameters! Use --help to get more information.");

What if argc is 0? Yes, that *is* possible on any Unix like system,
which includes MacOS X

> if (argc == 2 && argv[1] == "--help")
printf("Just test, you are free now.");

if (argv[1][0] == "-")
printf("This does not work?");

return 0;
}

Two questions:
1) How can I compare parameters to string, maybe I should use sprintf
and later try comparing? Or maybe there is direct way of doing it?
2) How can I get first char of the first parameter? (It's kinda hard
to understand how to write this)

The compiler should give you a warning for the second and last. You are
comparing a character to a string. You need '-' to create a char
constant, strcmp() to compare
if( strcmp(argv[1], "-help") == 0)
{

}

When you've sorted this out you might like to see my options parser, on
the website.

The OP is more likely to find the POSIX function getopt or the GNU
function getopt_long useful since he is almost certainly trying to
replicate their behaviour. For help with the POSIX getopt function the
OP should ask in comp.unix.progr ammer, possibly one of the GNU groups
for getopt_long.
--
Flash Gordon

[Malcolm McLean]

"Flash Gordon" <sp**@flash-gordon.me.ukwro te in message
news:pq******** ****@news.flash-gordon.me.uk...

Malcolm McLean wrote, On 20/02/08 18:00:

>>
"david" <Da************ *****@gmail.com wrote in message
news:17******* *************** ************@60 g2000hsy.google groups.com...

>>Code:
#include <stdio.h>
#include <strings.h>
#include <stdlib.h>

int main (int argc, char const *argv[])
{
if (argc == 1)
printf("No parameters! Use --help to get more information.");

What if argc is 0? Yes, that *is* possible on any Unix like system, which
includes MacOS X

>> if (argc == 2 && argv[1] == "--help")
printf("Just test, you are free now.");

if (argv[1][0] == "-")
printf("This does not work?");

return 0;
}

Two questions:
1) How can I compare parameters to string, maybe I should use sprintf
and later try comparing? Or maybe there is direct way of doing it?
2) How can I get first char of the first parameter? (It's kinda hard
to understand how to write this)

The compiler should give you a warning for the second and last. You are
comparing a character to a string. You need '-' to create a char
constant, strcmp() to compare
if( strcmp(argv[1], "-help") == 0)
{

}

When you've sorted this out you might like to see my options parser, on
the website.

The OP is more likely to find the POSIX function getopt or the GNU
function getopt_long useful since he is almost certainly trying to
replicate their behaviour. For help with the POSIX getopt function the OP
should ask in comp.unix.progr ammer, possibly one of the GNU groups for
getopt_long.

My options parser depends only on the standard library. The alternatives you
suggest may not be available on the OP's platform.

--
Free games and programming goodies.
http://www.personal.leeds.ac.uk/~bgy1mm

[Flash Gordon]

david wrote, On 20/02/08 19:59:

I know about the else, I just wrote it for small example not thinking
much about if statements. Next time (if there will be one I will try
not to do this and write as much correct code as I can).

The more effort you put in to writing your code the more effort people
are likely to put in to helping you.

I am reading this group from Google, there could I find FAQ of this
group?

When I search for comp.lang.c FAQ in Google (rather than Google Groups)
it is the first hit. http://c-faq.com/
--
Flash Gordon